Molar mass of MgCl2 is 95gmol-1. So there are 0.566 moles in this mass.
The answer is o,565 mol for anhydrous magnesium chloride.
7.35 moles Li.
1.6198 mol
1 mol of MgS2O3 = 136.4332 g
2 mol of MgS2O3 = 272.8664 g
3 mol of MgS2O3 = 409.2996
# of moles = grams of substance / molar mass of substance molar mass of Barium =137.33 grams/mole #moles of Barium = 22.3 grams/ 137.33 grams/mole = 0.162382582 moles
how many moles in 0.550 g of lithium
For an element such as lithium, the technically correct term is "gram atomic mass" instead of "mole", and for lithium, the gram atomic mass is about 6.941. Therefore, the answer to the question is (5.48)(6.941) or 37.5 grams, to the justified number of significant digits.
Because 2Li + O2 --> Li2O2 moles Li produces 1 mole Li2O3.04Li + --> 1.52 O2 --> 1.52 Li2O1.52 moles Li2O arw formed.
15g Li * (1mol Li / 6.941g Li) = 2.16 mol Li
The answer is 1,668.10-4 moles.
0,0864 moles of lithium contain 0,6 g Li.
It is 53M
37.5
# of moles = grams of substance / molar mass of substance molar mass of Barium =137.33 grams/mole #moles of Barium = 22.3 grams/ 137.33 grams/mole = 0.162382582 moles
how many moles in 0.550 g of lithium
671
The answer is: 2,96 moles.
The answer is 0,274 moles.
You find the number of atoms from the number of grams of a given substance by:Find the Moles of the Substance by multiplying the grams of the substance by the molar mass of the substance. ( Molar mass equals mass of substance per 1 mole of substance.)Grams x Molar Mass of Substance = Moles of SubstanceTake the moles of the substance and multiply it by Avogadro's Number (the number of atoms in 1 mole of substance, or simply 6.022x1023).Moles of Substance x Avogadro's Number (6.022x1023) = atoms of Substance
The answer is 902,45 g.
AlPO4 6.5 moles AlPO4 (121.95 grams/1 mole AlPO4) = 792.675 grams of AlPO4 ( you do sigi figis )