How many moles are in 6.5 moles of CH4?
It is just as the number.It has 6.5 moles in it
4 moles of ch4
Molar mass of methane, CH4 is 12.0 + 4.0 = 16.0 g/mole482 g x 1 mole/16.0 g = 30.1 moles CH4 (to 3 significant figures)
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
5.01 moles methane (CH4) 80.16g CH4 | 1 mol CH4 ---- 1 | 16g CH4
Approx 0.62 moles.
1 mole CH4 = 16.042g CH4 96g CH4 x 1mol CH4/16.042g CH4 = 6.0 moles CH4 (rounded to two significant figures)
How many molecules in CH4?
CH4 + 2 H2O = 3 H2 + CO2 8 moles CH4 produce 8 x 3 moles H2, which is 24.
2.3 grams CH4 (1 mole CH4/16.042 grams) = 0.14 moles methane ================
1 moles of CH4 has 4 moles of H atoms
2 moles CH4 (6.o22 X 10^23/1 mole CH4) = 1.0 X 10^24 moles of methane
0,289 g of methane CH4 is equivalent to 0,018 moles.
2.45 X 10^23 molecules CH4 (1 mole CH4/6.022 X 10^23) = 0.407 moles CH4
The equation for complete combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OSo, each 1 mole of CH4 requires 2 moles of O2. Therefore 3.0 moles of CH4 requires 6.0 moles O2.
156 grams CH4 (1 mole CH4/16.042 grams) = 9.72 moles of methane ==================
In 3 moles of CH4, there are 18.06 x 10^23 times Hydrogen atoms.
There are 4 Hydrogen atoms in 1 mol of CH4 so in 2 moles there will be 8.
7,98 moles of oxygen are needed to completely oxidize 64g CH4.
Molar mass CH4 = 16.0 g/mole6.07 g x 1 mole/16.0 g = 0.379 moles (to 3 significant figures)
How many moles of product would be produced if 0.500 mole of the first reactant were to react completely CO2 4H2 CH4 2H2O?
CO2 + 4H2 --> CH4 + 2H2O 0.500 moles CO2 (1 mole CH4/1 mole CO2) = 0.500 moles CH4 0.500 moles CO2 (2 moles H2O/1 mole CO2) = 1.00 moles H2O -------------------------------------------------------------------------------------add = 1.50 moles total product ====================
18 moles of oxygen are needed.
5.60 moles CH4 (4 moles H/1 mole CH4)(1.008 grams/1 mole H) = 22.6 grams of hydrogen ==================
How many moles of methane are produced when 82.6 moles of carbon dioxide gas react with excess hydrogen gas?
CO2+4H2 = CH4 + 2H20 (Balanced) 82.6 Moles. The Ratio is 1 Mol CH4 over 1 Mol CO2. So... 82.6 Mol CO2 * 1 Mol CH4/1 Mol CO2= 82.6 Moles of CH4
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO2 1 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH4 0.0625 moles CH4 ==> 0.0625 moles CO2 0.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2 Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
No. of moles = Given mass of element or compound/ molar mass of element or compound. Molar mass of Methane(CH4) = 16 g No. of moles of Methane in 345g = 345/16=21.562 moles.
Divide 96 by molecular mass.So the answer is 6mol
First divide 4 by 16.So answer is 0.25
2,8 moles is of course equivalent to 2,8 moles ! Probable is a spelling error in your question.
4.66715966 × 1024
It depends on temperature,pressure and volume.THese are needed to find number of moles
There are 0.75 moles in it.You have to devide 12 by molecular mass
Given the equation ch4 plus 2o2 yield CO2 plus 2h2o how many grams of CO2 will be made by the reaction of 7 moles of ch4 with 44 moles of O2?
it will have about 14
One molecule has four H atoms.So two moles have 8 moles
First, determine molar mass of CH4: C:12g/mol + 4x H:1g/mol= 16g/mol Then divide by the number of grams. 64g/(16g/mol)= 4 moles of CH4
0.86 moles CH4 (4 mole H/1 mole CH4)(6.022 X 10^23/1 mole H) = 2.1 X 10^24 atoms of hydrogen --------------------------------------------
The equation for a complete combustion reaction of CH4 is : CH4 + 2 O2 = CO2 + 2 H2O, showing that one mole of carbon dioxide is formed for each mole of CH4 burned. Therefore, the answer is 44 moles of CO2 formed.
What mass of water is produced from the complete combustion of 1.10 and times10 and minus3 g of methane?
Methane is CH4. Combustion is CH4 + 2O2 ==> CO2 + 2H2O1 mole CH4 produces 2 moles H2O moles CH4 used = 1.1x10^-3 g x 1 mole/16 g = 6.875x10^-5 moles moles H2O produced = 6.875x10^-5 moles CH4 x 2 moles H2O/mole CH4 = 1.375x10^-4 moles mass H2O produced = 1.375x10^-4 moles x 18 g/mole = 2.475x10^-3 g = 2.48 mg (3 sig.figs)
Divide mass by molecular mass.640/16.So the answer is 40
That's a tricky question, because one molecule of CH4 is simply that, one atom of carbon and 4 atoms of Hydrogen. Moles are a UNIT used to transform atoms (which we cannot measure individually in the lab) into practical units such as grams (which we can measure). The moles of CH4 depend on the mass, in SI units of grams, that you have of this substance. The molecular weight of CH4 is 16 g/mol (12… Read More
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
Balanced equation. CH4 + 2O2 -> CO2 + 2H2O one to one, but set-up anyway and limiting reacting known 2.0 moles CH4 (1 mole CO2/1 mole CH4) = 2.0 moles CO2 produced ( by the way, those numbers are subscripts, not superscripts )
One mole is equal to 6.022 x 1023 of anything. In this case, we are looking for molecules. So 1 mole=6.022 x 1023 molecules. We have 2.3 moles, so we want to know how many molecules are there. 2.3 mol CH4 x 6.022x1023 molecules CH4 / mol CH4 = 1.38x1024 molecules of CH4
Divide mass by molecular mass.So the answer is 3
CH4+2O2---->CO2+2H2O.One mole gives one mole of CO2.So 44 moles of CO2 is formed
The formula of methane is CH4. So 4 times that = 4 carbon moles and 8 moles hydrogen.
2 O2 + CH4 -> CO2 + 2 H2O For every mole of CH4, there is 2 moles of O2
That depends on the conditions the CH4 is subjected to. At STP, CH4 would be a gas with 22.4 liters/mole (0.0224 m3/mole) or 44.6 moles/m3. If you have it at cryogenic temperatures and high pressures like the atmosphere of Jupiter, the density will be different.
Simply multiply by molecular mass. 16*6.So the mass produced is 96g
You have to multiply it by !6.It ia the molar mass