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How many moles of sodium oxide will react with 42.0 moles of water?
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).
How many moles of sodium oxide will be produced with 10 moles of sodium react with oxygen?
1 mole of Sodium Chloride weighs 58.5 grams (1 mole is the same as the molecular weight of a compound. The molecular mass of Sodium Chloride- NaCl is 23 [Na atomic mass] + 35.5 [Cl atomic mass] which is equal to 58.5 grams).Thus 10 moles would weigh 10x58.5 grams = 585 grams.The answer is 585 grams.
How many moles will be produced by 4Na plus O2 - 2Na2O?
You have answered the question for yourself. 4 Na + O2 = 2Na2O The molar ratios are 4:1 :: 2 The answer is '2'.
How many grams of sodium oxide will be formed if 46 grams of sodium are use?
46 grams of sodium is 2 moles. 2 mol of sodium forms 1 mol of sodium oxide. So it makes 62 g of sodium oxide.
How many oxide ions are present in 0.34 mol of sodium oxide?
0.34 moles Na2O (1 mole O 2-/1 mole Na2O)(6.022 X 1023/1 mole O 2-) 2.1 X 1023 ions of oxygen ================
How many moles of sodium oxide will be produced when 10 moles of sodium react with oxygen 4Na OËÃ æ 2NaËÃO?
When 4 moles of sodium react with oxygen, 2 moles of sodium oxide are produced (according to the balanced equation). Therefore, when 10 moles of sodium react, 5 moles of sodium oxide will be produced.
Sodium will react with oxygen to form sodium oxide. Use the formula below to determine how many grams of sodium oxide will be formed if 46 grams of sodium are used in the reaction.?
62 grams a+
Sodium will react with oxygen to form sodium oxide Use the formula below to determine how many grams of sodium oxide will be formed if 46 grams of sodium are used in the reaction?
The balanced equation for the reaction is: 4 Na + O2 -> 2 Na2O. From the equation, 4 moles of sodium will react to form 2 moles of sodium oxide. Calculate the molar mass of Na2O (sodium oxide) to find out how many grams will be formed.
How many moles of sodium oxide will react with 42.0 moles of water?
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).
How many moles of sodium oxide will be produced with 10 moles of sodium react with oxygen?
1 mole of Sodium Chloride weighs 58.5 grams (1 mole is the same as the molecular weight of a compound. The molecular mass of Sodium Chloride- NaCl is 23 [Na atomic mass] + 35.5 [Cl atomic mass] which is equal to 58.5 grams).Thus 10 moles would weigh 10x58.5 grams = 585 grams.The answer is 585 grams.
How many moles of sodium oxide will be produced when 10 moles of sodium react with oxygen This is the formula for the reaction?
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
How many moles will be produced by 4Na plus O2 - 2Na2O?
You have answered the question for yourself. 4 Na + O2 = 2Na2O The molar ratios are 4:1 :: 2 The answer is '2'.
How many grams of sodium oxide will be formed if 46 grams of sodium are use?
46 grams of sodium is 2 moles. 2 mol of sodium forms 1 mol of sodium oxide. So it makes 62 g of sodium oxide.
HOW many moles are in 4.5 moles of sodium fluoride?
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
How many oxide ions are present in 0.34 mol of sodium oxide?
0.34 moles Na2O (1 mole O 2-/1 mole Na2O)(6.022 X 1023/1 mole O 2-) 2.1 X 1023 ions of oxygen ================
How many moles of sodium in 6.5 gram of sodium?
The answer is 0,111 moles.
How many moles of sodium are in 4.0 moles of NaCl?
Every formula unit of sodium chloride has one sodium atom. Therefore, there are 4.0 moles of sodium ions in 4.0 moles of NaCl.
