H3PO4 + 1 OH- --> H2PO4- + 1 H2O
H3PO4 + 2 OH- --> HPO42- + 2 H2O
H3PO4 + 3 OH- --> PO43- + 3 H2O
Every 1mol of H₃SO₄, there are 3 mol of NaOH to reacted with
3 moles of NaOH per mole of H3PO4 or 120 g NaOH to 98 g H3PO4
Depends how much of it you have.
Let us find moles first. Molarity = moles of solute/Liters of solution ( 750 ml = 0.750 Liters ) 0.375 M Na2SO4 = moles Na2SO4/0.750 Liters = 0.28125 moles Na2SO4 =================== 0.28125 moles Na2SO4 (142.05 grams/1 mole Na2SO4) = 39.95 grams Na2SO4 needed ---------------------------------------you do significant figures!
Sodium is a metal element. Mass of 3.8 moles is 87.4g.
M.W. of the given compound is 3x23+1x31+4x16=164 in Na3PO4 3 moles of Na+ ions are produces i.e., 1mole weighs 164g contain 3x6.023x10^23 Na+ ions ?5.43g contain = 5.43g x 3 moles Na+ x 6.023x10^23 / 164 g/mol Na+ ions=0.598x10^23
The formula mass of sodium triphosphate, Na3PO4 is 3(23.0)+31.0+4(16.0)=164.0 Amount of sodium triphosphate = 10/164.0 = 0.0610mol
Na3PO4
Molarity = moles of solute/Liters of solution 0.300 M Na3PO4 = moles Na3PO4/2.50 Liters = 0.75 moles Na3PO4
12 moles
1,5665 moles barium phosphate
I assume double displacement reaction. Balanced equation. 3AgNO3 + Na3PO4 -> Ag3PO4 + 3NaNO3 2.00 moles sodium phosphate ( 3 moles AgNO3/1 mole Na3PO4) = 6.00 moles silver nitrate needed =========================
2,196.10-12 pmol of Na3PO4. (p is pico)
Let us find moles first. Molarity = moles of solute/Liters of solution ( 750 ml = 0.750 Liters ) 0.375 M Na2SO4 = moles Na2SO4/0.750 Liters = 0.28125 moles Na2SO4 =================== 0.28125 moles Na2SO4 (142.05 grams/1 mole Na2SO4) = 39.95 grams Na2SO4 needed ---------------------------------------you do significant figures!
the formula does not show how many moles are in a compound, but it tells how many atoms of an element that are in the compound...
Sodium is a metal element. Mass of 3.8 moles is 87.4g.
M.W. of the given compound is 3x23+1x31+4x16=164 in Na3PO4 3 moles of Na+ ions are produces i.e., 1mole weighs 164g contain 3x6.023x10^23 Na+ ions ?5.43g contain = 5.43g x 3 moles Na+ x 6.023x10^23 / 164 g/mol Na+ ions=0.598x10^23
The formula mass of sodium triphosphate, Na3PO4 is 3(23.0)+31.0+4(16.0)=164.0 Amount of sodium triphosphate = 10/164.0 = 0.0610mol
Sodium Phosphate
Na3PO4