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How many moles are in 10 grams in sodium phosphate?
To calculate the number of moles in 10 grams of sodium phosphate (Na3PO4), we first need to determine the molar mass of Na3PO4, which is approximately 164.0 g/mol. Then, we can use the formula: moles = mass / molar mass. Therefore, for 10 grams of sodium phosphate, there would be approximately 0.061 moles present.
How many grams of Na3PO4 will be needed to produce 425 mL of a solution that has a concentration of Na plus ions of 0.900 M?
Let us find moles first. Molarity = moles of solute/Liters of solution ( 750 ml = 0.750 Liters ) 0.375 M Na2SO4 = moles Na2SO4/0.750 Liters = 0.28125 moles Na2SO4 =================== 0.28125 moles Na2SO4 (142.05 grams/1 mole Na2SO4) = 39.95 grams Na2SO4 needed ---------------------------------------you do significant figures!
What mass of the precipitate could be produced by adding 100.0ml of 0.887 m agno3 to a na3po4 solution assume that the sodium phosphate reactant is present in excess?
To find the mass of the precipitate that forms when 100.0mL of 0.887M AgNO3 is added to a Na3PO4 solution, you need to determine the limiting reactant. Since Na3PO4 is in excess, AgNO3 is the limiting reactant. Calculate the moles of AgNO3 using its molarity and volume, then use the mole ratio between AgNO3 and the precipitate to find the moles of the precipitate. Finally, convert the moles of the precipitate to mass using its molar mass.
What is the percentage by mass of phosphorus in Na3PO4?
Phosphorus has a molar mass of 30.97 g/mol, while the molar mass of Na3PO4 is 163.94 g/mol. To find the percentage by mass of phosphorus in Na3PO4, divide the molar mass of phosphorus by the molar mass of Na3PO4, and multiply by 100. This gives a percentage by mass of approximately 18.9% phosphorus in Na3PO4.
How many moles are in Na3PO4?
As given 'Na3PO4' it is impossible to tell, because you also need the mass of sodium phosphate. Then use the eq'n moles = mass(g) / Mr From the Periodic Table we can calculate the Mr. Naa x 3 = 23 x 3 = 69 P x 1 = 31 x 1 = 31 O x 4 = 16 x 4 = 64 69 + 31 + 64 = 164 164 is the Relative molecular mass (Mr) of sodium phosphate. However, mass(g) = 1 mole X 164(Mr) mass of 1 mole = 164 grams. Similarly mass(g) = 2 moles X 164(Mr) mass of 2 moles = 328 grams. et seq., So you need to know the mass in order to calculate the moles.
How many moles are in 10 grams in sodium phosphate?
To calculate the number of moles in 10 grams of sodium phosphate (Na3PO4), we first need to determine the molar mass of Na3PO4, which is approximately 164.0 g/mol. Then, we can use the formula: moles = mass / molar mass. Therefore, for 10 grams of sodium phosphate, there would be approximately 0.061 moles present.
How many moles of sodium ions are present in 2.50 L of 0.300 M Na3PO4?
There are 0.75 moles of sodium ions present in 2.50 L of 0.300 M Na3PO4. Each formula unit of Na3PO4 has 3 sodium ions. So, for every mole of Na3PO4, there are 3 moles of sodium ions. Calculating the moles of sodium ions: 2.5 L * 0.300 mol/L * 3 mol Na+ / 1 mol Na3PO4 = 0.75 moles of Na+.
How many grams of Na3PO4 will be needed to produce 425 mL of a solution that has a concentration of Na plus ions of 0.900 M?
Let us find moles first. Molarity = moles of solute/Liters of solution ( 750 ml = 0.750 Liters ) 0.375 M Na2SO4 = moles Na2SO4/0.750 Liters = 0.28125 moles Na2SO4 =================== 0.28125 moles Na2SO4 (142.05 grams/1 mole Na2SO4) = 39.95 grams Na2SO4 needed ---------------------------------------you do significant figures!
What mass of the precipitate could be produced by adding 100.0ml of 0.887 m agno3 to a na3po4 solution assume that the sodium phosphate reactant is present in excess?
To find the mass of the precipitate that forms when 100.0mL of 0.887M AgNO3 is added to a Na3PO4 solution, you need to determine the limiting reactant. Since Na3PO4 is in excess, AgNO3 is the limiting reactant. Calculate the moles of AgNO3 using its molarity and volume, then use the mole ratio between AgNO3 and the precipitate to find the moles of the precipitate. Finally, convert the moles of the precipitate to mass using its molar mass.
How many moles are in 2 Na3PO4 3 MgCl2--Mg3PO42 6NaCl?
12 moles
What is the percentage by mass of phosphorus in Na3PO4?
Phosphorus has a molar mass of 30.97 g/mol, while the molar mass of Na3PO4 is 163.94 g/mol. To find the percentage by mass of phosphorus in Na3PO4, divide the molar mass of phosphorus by the molar mass of Na3PO4, and multiply by 100. This gives a percentage by mass of approximately 18.9% phosphorus in Na3PO4.
100ml of 0.1M NaOH 50ml of 0.2M BaCl2 or 75ml of 0.15M Na3PO4 are strong electrolytes.Which contains the largest number of ions?
To determine which solution contains the largest number of ions, we need to calculate the total moles of ions produced by each solution. NaOH (100ml of 0.1M): 0.1 moles/L × 0.1 L = 0.01 moles of NaOH → produces 0.01 moles Na⁺ and 0.01 moles OH⁻ = 0.02 moles of ions. BaCl2 (50ml of 0.2M): 0.2 moles/L × 0.05 L = 0.01 moles of BaCl2 → produces 0.01 moles Ba²⁺ and 0.02 moles Cl⁻ = 0.03 moles of ions. Na3PO4 (75ml of 0.15M): 0.15 moles/L × 0.075 L = 0.01125 moles of Na3PO4 → produces 0.03375 moles Na⁺ and 0.01125 moles PO4³⁻ = 0.045 moles of ions. Therefore, Na3PO4 contains the largest number of ions.
In the formula for sodium phosphate Na3PO4 how many moles of sodium are represented?
There are 3 moles of sodium represented in one mole of sodium phosphate (Na3PO4). This is because the subscript 3 in Na3PO4 indicates that there are 3 sodium ions for every molecule of sodium phosphate.
How many moles of silver nitrate would be required to react with 2.00 moles of sodium phosphate?
I assume double displacement reaction. Balanced equation. 3AgNO3 + Na3PO4 -> Ag3PO4 + 3NaNO3 2.00 moles sodium phosphate ( 3 moles AgNO3/1 mole Na3PO4) = 6.00 moles silver nitrate needed =========================
How many moles are in Na3PO4?
As given 'Na3PO4' it is impossible to tell, because you also need the mass of sodium phosphate. Then use the eq'n moles = mass(g) / Mr From the Periodic Table we can calculate the Mr. Naa x 3 = 23 x 3 = 69 P x 1 = 31 x 1 = 31 O x 4 = 16 x 4 = 64 69 + 31 + 64 = 164 164 is the Relative molecular mass (Mr) of sodium phosphate. However, mass(g) = 1 mole X 164(Mr) mass of 1 mole = 164 grams. Similarly mass(g) = 2 moles X 164(Mr) mass of 2 moles = 328 grams. et seq., So you need to know the mass in order to calculate the moles.
How many moles in 3.6x10-10g sodium phosphate?
2,196.10-12 pmol of Na3PO4. (p is pico)
Number of oxygen atoms in 2.35 moles sodium phosphate?
There are 7.05 moles of oxygen atoms in 2.35 moles of sodium phosphate, as there are 3 oxygen atoms in each formula unit of sodium phosphate (Na3PO4).
