6.022 x 10e23
400 grams of nickel sulphate (anhydrous) is equivalent to 2,58 moles.
The answer is 2,4 moles.
400 g of calcium cabonate is equal to 3,996 moles.
.400 moles
The answer is 0,16 moles.
where is the heating element on a kenmore series 400
The concentration of a solution is given by the formula: concentration = moles of solute / volume of solution in liters. However, to determine the concentration in this case, we need to know the moles of HCl in the solution. Given that the concentration is 0.5 M, it means there are 0.5 moles of HCl in every liter of solution. To find out how many moles are in 400 ml (0.4 L) of 0.5 M HCl solution, we use the formula: moles = concentration x volume. moles = 0.5 M x 0.4 L = 0.2 moles. Therefore, the concentration of 400 ml of 0.5 M HCl solution is 0.5 M.
And they are expensive to replace... (i replaced one @ $400)
So you want 0.04M but you have 400ml, not a litre. 0.04/1000*400 is 0.016 moles wanted. 0.016*40 (molecular weight) is 0.64g
To calculate the number of moles of NaI in 50.0mL of a 0.400M solution, you first need to convert the volume to liters by dividing by 1000 (since 1L = 1000mL). Then, use the formula moles = Molarity x Volume (in liters) to find the number of moles of NaI. In this case, it would be 0.400 mol/L x 0.050 L = 0.020 moles of NaI.
No, a 400 volt heater element cannot be safely operated on a 230 volt supply. To avoid damaging the element and potential safety hazards, it is important to match the voltage rating of the heater element with the supply voltage.
By definition, a 0.61M sodium nitrate solution contains 0.61 moles of sodium nitrate per liter, which is equivalent to 0.61 mmol/ml. Therefore, the volume of this solution required to contain 400mmol is 400/0.61 or 6.6 X 102 ml, to the justified number of significant digits.