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The molar mass of barium sulfate, BaSO4 is 233.4

Amount of BaSO4 = mass of sample / molar mass = 14.2/233.4 = 0.0608mol

0.0608 moles of BaSO4 are conained in a 14.2g pure sample.

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Q: How many moles contained in 14.2g of barium sulfate?
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