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150.0 g O2 x 1 mole O2/32 g O2 = 4.688 moles O2
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how many moles of NO2 are in 7.4 mol N2O5?
N2O5(g) → 4NO2(g) + O2(g)
What is the total number of moles of O2(g) required for the complete combustion of 1.5 moles of C3H8(g)?
C3H8 + 5O2 ==> 3CO2 + 4H2O balanced equationmole ratio O2:C2H8 = 5:1 1.5 moles C3H8 x 5 moles O2/mole C3H8 = 7.5 moles O2 needed
How many grams of CO2 are used when 6.5 g of O2 are produced?
1CO2 ==> 1O26.5 g O2 x 1 mol/32 g = 0.203 moles O2grams of CO2 = 0.203 moles x 44 g/mole = 8.9 grams
How many grams of water can be produced from 50 grams of hydrogen and 300 grams of oxygen?
2H2 + O2 ===> 2H2O50 grams H2 x 1 mole H2/2 g = 25 moles H2300 grams O2 x 1 mole O2/32 g = 9.375 moles O2Limiting reactant is O2, so maximum moles of H2O formed = 9.375 O2 x 2H2O/1 O2 = 18.75 molesgrams H2O = 18.75 moles H2O x 18 g/mole = 337.5 g H2O = 340 g (to 2 significant figures)
How many grams are there in 2.047 moles of O2?
For this you need the atomic (molecular) mass of O2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.047 moles O2 × (32.0 grams) = 65.5 grams O2
How many moles are in 64 g of oxygen?
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
How many grams are in 0.800 moles of oxygen?
0,800 moles of oxygen (O2) is equivalent to 25,6 g.
What number of moles of o2(g) is required to react with 3.6 mole so2(g) in 2so2(g) o2(g) - 2so3(g)?
1,8 moles of oxygen are necessary.
how many moles of NO2 are in 7.4 mol N2O5?
N2O5(g) → 4NO2(g) + O2(g)
How many moles of O2 are needed to burn 1.35mol of C8H18?
16,875 moles of oxygen are needed.
What is the total number of moles of O2(g) required for the complete combustion of 1.5 moles of C3H8(g)?
C3H8 + 5O2 ==> 3CO2 + 4H2O balanced equationmole ratio O2:C2H8 = 5:1 1.5 moles C3H8 x 5 moles O2/mole C3H8 = 7.5 moles O2 needed
How many moles of O2 g are produced by the reaction of 156 g CO2 g with excess KO2?
The reaction of carbon dioxide and potassium oxide is 4KO2 + 2CO2 = 2K2CO3 + 3O2. 156 grams of CO2 is 3.54 moles, which will produce 5.31 moles of O2.
How many grams of CO2 are used when 6.5 g of O2 are produced?
1CO2 ==> 1O26.5 g O2 x 1 mol/32 g = 0.203 moles O2grams of CO2 = 0.203 moles x 44 g/mole = 8.9 grams
When 3.00 g of Mg is ignited in 2.20 g of pure oxygen what is the limiting reactant and what is the theoretical yield of MgO?
Moles Mg = 3.00 g / 24.312 g/mol =0.123 Moles O2 = 2.20 / 32 g/mol = 0.0688 2 Mg + O2 >> 2 MgO the ratio between Mg and O2 is 2 : 1 0.123 / 2 = 0.0615 moles O2 needed we have 0.0688 moles of O2 so O2 is in excess and Mg is the limiting reactant we get 0.123 moles of MgO => 0.123 mol x 40.31 g/mol =4.96 g
How many grams of water can be produced from 50 grams of hydrogen and 300 grams of oxygen?
2H2 + O2 ===> 2H2O50 grams H2 x 1 mole H2/2 g = 25 moles H2300 grams O2 x 1 mole O2/32 g = 9.375 moles O2Limiting reactant is O2, so maximum moles of H2O formed = 9.375 O2 x 2H2O/1 O2 = 18.75 molesgrams H2O = 18.75 moles H2O x 18 g/mole = 337.5 g H2O = 340 g (to 2 significant figures)
How many moles of H2O are product from reaction of 355 g of O2?
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
