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How many moles in 300g of sulfur?


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Answered 2015-12-08 20:54:01

300 g sulfur is equivalent to 9,357 moles.

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Mass = Moles x Ar = 12.5 x 24 = 300g


I mole of sulfur atoms is 32 g. Thus there are 300/32 moles in 300 g, i.e. 9.375 moles.


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moles = mass / molar mass assuming that sulfur is simply represented by "S", then the molar mass is 32.07, as seen in the periodic table (meaning that each sulfur atom is 32.07 grams per mole. so moles of sulfur = 80.25 / 32.07 = 2.50 moles


7.71 grams sulfur (1 mole S/32.07 grams) = 0.2404 moles of sulfur


2 moles sulfur dioxide (6.022 X 1023/1 mole SO2) = 1 X 1024 molecules of sulfur dioxide ===========================


Sulfur dioxide is SO2, so there are 2 moles of oxygen for each mole of sulfur. In 25 moles of SO2, there are 25 moles of S, so there must be 50 moles of oxygen, or 25 moles of diatomic oxygen gas (O2).


Zn + S ==> ZnSmoles Zn = 25 g x 1 mol/65.4 g = 0.38 moles Znmoles S = 300 g x 1 mol/32 g = 9.38 moles Smoles S in excess = 9.38 - 0.38 = 9.00 molesmass S in excess = 9 moles x 32g/mol = 288 g = 280 g (to 2 significant figures)


No. of moles=given mass/gram molecular mass =16/16 =1


one mole of sulfur has a mass of 32 g --- its atomic mass. so just multiply by 2,4 moles



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