The molecular mass of iron(III) chloride is 55.8 + 3(35.5) = 162.3
Amount of iron (III) chloride in a 80.5g pure sample = 80.5/162.3 = 0.496mol
8200 grams iron (1 mole Fe/55.85 grams)
= 146.8 moles iron
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80 grams of ferric oxide is equal to 0,5 mol.
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
Approx 3.997 moles.
4 moles - APEX
9 moles of Fe(No3)
Find iron (Fe) on the periodic table the biggest number (at the bottom) is the mass number 1 mole is that number in grams. you can work it out from there.
Approx 3.997 moles.
55.8 moles
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
6 moles
Approx 3.997 moles.
4 moles - APEX
23 grams iron ( 1mole Fe/55.85 grams) = 0.41 moles of iron
55.8 moles
For this you need the atomic mass of Fe. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel..410 grams Fe / (55.9 grams) = .00733 moles Fe
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
9 moles of Fe(No3)