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12.57 grams KCl (1mol KCl/74.55g ) = 0.1686 moles
3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
4.1 X 10^-12g O (1mol O/16g O )(6.022 X 10^23/1mol O )(1mol atoms O/6.022 X 10^23 ) = 2.56 X 10^-13 moles of atoms
20.67 grams NaCl (1mol NaCl/58.44 g NaCl) = 0.3537 moles of sodium chloride
1 mole NO = 30.0061g 345.6g NO x 1mol/30.0061g = 11.52mol NO
2.49x10-1mol NH3Source: e2020
(1kg C2H6O2 )(1000g/1kg)(1mol/62g) = 16.1 moles
12.57 grams KCl (1mol KCl/74.55g ) = 0.1686 moles
100 grams MgCO3 (1mol MgCO3/84.32g) = 1.19 moles of MgCO3
(76 g F) * (1mol F/ 19g F) = 4 moles of F
3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
4.1 X 10^-12g O (1mol O/16g O )(6.022 X 10^23/1mol O )(1mol atoms O/6.022 X 10^23 ) = 2.56 X 10^-13 moles of atoms
20.67 grams NaCl (1mol NaCl/58.44 g NaCl) = 0.3537 moles of sodium chloride
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
14.2g Fe2O3 (1mol Fe2O3/159.7g(2mol Fe/1mol Fe2O3) = 0.178 moles Fe
Step 1: Convert the mass of each element to moles.4.0g H x 1mol H/1.00794g H = 4.0 moles H28g N x 1mol N/14.0067g N = 2.0 moles NStep 2: Divide each mole value by the smallest number of moles calculated.H = 4.0 moles/2.0 moles = 2N = 2.0 moles/2.0 moles = 1Empirical Formula = NH2
Balanced equation first. 2Na + 2HCl >> 2NaCl + H2 25 grams Na (1mol Na/22.99g )(1mol H2/2mol Na ) = 0.54 moles of H2 produced.