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The silver nitrate solution (AgNO3) provides the silver in silver chloride.
FeCl3 +KSCN + AgNO3
AgNO3 powder is white but a little grey solid.
The chemical reaction is:2 AgNO3 + Na2S = 2 NaNO3 + Ag2S(s)
Unfortunately this question is a complicated mathematical equation that can not be completed in 750 characters. There is a complex equation, where the user would in put the volume of the ions and the solution and calculate the solution in that manner.
Of course 0.100 mol of AgCl.
The silver nitrate solution (AgNO3) provides the silver in silver chloride.
12.4g
agno3
NaCI + AgNO3 >>>>> NaNO3 + AgCI (white ppt.)
Get moles silver nitrate. 255 grams AgNO3 (1 mole AgNO3/169.91 grams) = 1.5008 moles AgCO3 --------------------------------Now; Molarity = moles of solute/Liters of solution ( 1500 ml = 1.5 Liters ) Molarity = 1.5008 moles AgNO3/1.5 Liters = 1.00 M AgNO3 ---------------------
Molarity = moles of solute/liters of solution or, for our purposes moles of solute = liters of solution * Molarity moles of AgNO3 = 0,50 liters * 4.0 M = 2.0 moles of AgNO3 needed --------------------------------------
no because emf of cu ic less as compared to Agno3 as we keep agno3 in cu reaction will occour
Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can
Howe's solution- ammoniacal AgNo3-dental protective mixed with 1o% Formalin or Eugenol
The balanced equation is as follows: KIO3 + AgNO3 --> KNO3 + AgIO3
They will form NaNO3 in aqueous solution, and AgOH would precipitate out of solution. AgNO3(aq) + NaOH(aq) --> AgOH(s) + NaNO3(aq) This is an example of a double displacement/replacement reaction.