0.1mol
Molar mass CHCI3=119.368
65.2g/119.368=0.54621*3(which is the number of molecules of CI in the formula)= 1.64 mol
The answer is 0,0244 moles.
.100 Moles
0.100 moles
No. of moles=given mass/gram molecular mass =16/16 =1
Moles = Mass/ Relative Molecular Mass Aluminum forms Al2 compounds, so the relative molecular mass is 2 * 13 = 26. 856/26 = 32.9 (3sf)
Divide mass of 27 g H2O by its molar mass of 18.0 g.mol−1 H2O and you get the number of moles: 1.5 mole H2O
The atomic mass of B is 10.8Amount of B = mass of pure sample/molar mass = 31.78/10.8 = 2.94mol There are 2.94 moles of the element boron in a 31.78g pure sample.
0.010 moles The molar mass of H2SO4 is 98.1 grams per mole. To find out how many moles are present in a given mass, divide the mass by the molar mass. So: 1g/98.1g mol-1 is 0.010 mol.
No. of moles=given mass/gram molecular mass =16/16 =1
# of moles = grams of substance / molar mass of substance molar mass of Barium =137.33 grams/mole #moles of Barium = 22.3 grams/ 137.33 grams/mole = 0.162382582 moles
Mass (g) = Mr * Moles If you rearrange it, you get Moles = Mass/Mr Working with a 2dp periodic table you get: Moles = 2/1.01 =1.98 There are 1.98 moles of hydrogen in 2g of H2 gas.
The quantity that serves as a conversion factor between mass and number of moles is the molecular mass.
Moles = Mass/ Relative Molecular Mass Aluminum forms Al2 compounds, so the relative molecular mass is 2 * 13 = 26. 856/26 = 32.9 (3sf)
First we calculate the formula mass of the compound magnesium sulfate.Formula mass of MgSO4 = 24.3 + 32.1 + 4(16.0) = 120.4 Amount of MgSO4 in a 480g pure sample = 480/120.4 = 3.99mol There is approximately 4 moles of the compound present in a 480g sample.
.8 moles
The atomic mass of carbon, C is 12.0Amount of C = mass of sample/molar mass = 0.170/12.0 = 0.0142mol There are 0.0142 moles of carbon in a 0.170g pure sample.
Divide mass of 27 g H2O by its molar mass of 18.0 g.mol−1 H2O and you get the number of moles: 1.5 mole H2O
The molar mass of acetylsalicylic acid is 180.157 g/mol. There is a calculation involved in order to find the number of moles in a sample of ASA in which you divide the mass of your sample with the molar mass.
The atomic mass of B is 10.8Amount of B = mass of pure sample/molar mass = 31.78/10.8 = 2.94mol There are 2.94 moles of the element boron in a 31.78g pure sample.
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.