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76.2 mol Ag

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Gillian Watsica

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2y ago
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10y ago

You take 4.59 times 10 to the 25th and divide it by 3.002 times 10 to the 23. That should equal 76.47.

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12y ago

0.74559946861508 assuming you meant 10^23 instead of 1023

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11y ago

4.49 / 6.02 moles = 0.746 mole particles (of any kind), since NA = 6.02*1023 particles (of any kind) per mole, this is Avogadro's number.

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11y ago

1 mole Ag = 6.022 x 1023 atoms Ag

4.49 x 1023 atoms Ag x 1mol Ag/6.022 x 1023 atoms Ag = 0.746 mole Ag

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11y ago

The answer is 76,22 mol Ag.

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11y ago

The answer is 0,746 moles.

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7y ago

76,22 moles silver

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12y ago

76.2 mol Ag

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Q: How many moles of Ag contains 4.59x10 to the power of 25 atoms of Ag?
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