2C6H6 + 15O2 ==> 12CO2 + 6H2Omoles C6H6 combusted = 45.0 g x 1 mole/78 g = 0.577 moles
moles CO2 formed = 0.577 moles C6H6 x 12 moles CO2/2 moles C6H6 = 3.46 moles CO2
write the balanced reaction
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
times by 3
6 C4H10 + 39 O2 → 24 CO2 + 30 H2O
answer is 24 moles of carbon dioxide
This number is approx, 36,132.10ex23 molecules.
The balanced equation for complete combustion of C6H6 (hexane) is
2C6H6 + 15O2 ---> 12CO2 + 6H2O so there will be 12 moles of CO2 produced for every mole of C6H6
6 moles of carbon dioxide is equal to 264,06 g.
Two moles of carbon dioxide are produced.
Balanced equation first, 2C6H14 + 19O2 >> 12CO2 + 14H2O 84.4 moles hexane (12 moles CO2/2 moles C6H14) = 506.4 moles of CO2
Coconut oil is a very complex mixture; you need a specific equation for each component. But, finally only some products exist: carbon dioxide, water and and a small residue incombustible.
roots
Yes*. The empirical equation for this reaction is: 2C6H14 + 19O2 ---> 12CO2 + 14H2O. * n-Hexane, burned in an Iron III-catalyzed environment of pure oxygen gas, is oxidized completely. Intermediate products, such as peroxides are formed but the final products are carbon dioxide and water.
6c2h6+21o2=12co2+18h2o
2c6h14 + 15o2 -> 12co2 + 14h2o Stupid site again!! All letters are capitals.
C12H22O11+24CuO ® 12CO2 + 11H2O + 24Cu
I get 2C6H14+19O2------->12CO2+14H2O
2c6h14 + 15o2 -> 12co2 + 14h2o Stupid site again!! All letters are capitals.
Balanced equation first, 2C6H14 + 19O2 >> 12CO2 + 14H2O 84.4 moles hexane (12 moles CO2/2 moles C6H14) = 506.4 moles of CO2
When there is combustion of benzene the products formed are water and carbon dioxide. The equation for combustion of benzene is 2C6H6 + 15O2 ---> 12CO2 + 6H2O.
Coconut oil is a very complex mixture; you need a specific equation for each component. But, finally only some products exist: carbon dioxide, water and and a small residue incombustible.
C4H8(g) + 6 O2(g) --> 4 CO2(g) + 4 H2O(l)
roots
Yes*. The empirical equation for this reaction is: 2C6H14 + 19O2 ---> 12CO2 + 14H2O. * n-Hexane, burned in an Iron III-catalyzed environment of pure oxygen gas, is oxidized completely. Intermediate products, such as peroxides are formed but the final products are carbon dioxide and water.
6c2h6+21o2=12co2+18h2o
The chemical formula for benzene is C6H6. A combustion reaction requires O2 gas and forms H2O liquid and CO2 gas. The balanced equation for the combustion of benzene is 2C6H6(l) + 15O2(g) ---> 12CO2(g) + 6H2O(g).