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To determine the number of moles of ions present in a known volume of solution, follow this example:

HCl dissociates completely in water into H+ and Cl-, because this is a strong acid, and only strong acids, bases, and ionic compounds have the ability to dissociate completely.

This means one equivalent of HCl will generate one equivalent of H+ and Cl- ions; the same number of moles of HCl will generate the same number of moles for H+ and Cl-

HCl --> H+ + Cl-

Now determine the number of moles in the volume of your solution. Remember that 1M is another way to say 1 mole/L.

(2moles HCl/ 1L) x (1L) = 2 moles HCl

Since the equation states that 1 equivalent of HCl is 1 H+, the final answer is:

(2moles HCl/ 1L) x (1L) x (1 mole H+/1mole HCl) = 2 moles H+

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14y ago
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13y ago

Well, molarity (M) is defined as (moles of solute)/(Liters of solution). So first you should convert 200 mL to liters by dividing 200 by 1000 = 0.200 L. Then plug your info into the formula,

0.25 M = X/(0.200 mL), multiply by 0.200 mL to get X. Your answer should be

0.050 moles of HCl.

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13y ago

1 M = 1 mole/L

if you want 1 L then you should need 1 mole

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13y ago

Molarity = moles of solute/Liters of solution (50 ml = 0.05 Liters )

10 M HCl = moles HCl/0.05 Liters

= 0.5 moles HCl

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11y ago

0.0004 mole HCl

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7y ago

2 moles -OH

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11y ago

.2 moles

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Q: How many moles of H plus ions are present in one liter of 2 M HCl?
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