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How many atoms of H are in 2 mol of c8h18?
To determine the number of hydrogen atoms in 2 mol of C8H18, we first need to calculate the molar mass of C8H18. Carbon has a molar mass of approximately 12 g/mol, and hydrogen has a molar mass of approximately 1 g/mol. Therefore, the molar mass of C8H18 is (812) + (181) = 114 g/mol. Next, we use Avogadro's number (6.022 x 10^23) to calculate the number of molecules in 2 mol of C8H18, which is 2 mol * 6.022 x 10^23 molecules/mol. Since there are 18 hydrogen atoms in each molecule of C8H18, the total number of hydrogen atoms in 2 mol of C8H18 is 2 mol * 6.022 x 10^23 molecules/mol * 18 atoms/molecule = 2.17 x 10^25 hydrogen atoms.
0.400mol of octane is allowed to react with 0.800mol of oxygen Which is the limiting reactant?
To determine the limiting reactant, compare the moles of each reactant to the stoichiometry of the balanced. In this case, the balanced equation is: 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O The moles ratio between octane (C8H18) and oxygen (O2) is 2:25. Calculate the ratio for each reactant: Octane: 0.400 mol * (25 mol O2 / 2 mol C8H18) = 5.00 mol O2 needed Oxygen: 0.800 mol O2. Since the actual moles of oxygen available (0.800 mol) are greater than the moles needed for the reaction with octane (5.00 mol), oxygen is in excess and octane is the limiting reactant.
How many moles of O2 are needed to burn 1.50 moles of C8H18?
The balanced equation for the combustion of C8H18 is: C8H18 + 12.5O2 -> 8CO2 + 9H2O From the equation, you need 12.5 moles of O2 to burn 1 mole of C8H18. So, to burn 1.50 moles of C8H18, you would need 1.50 x 12.5 = 18.75 moles of O2.
How many moles of ions are produced when 2 mol of Na2CO3 dissociate?
Na2CO32 * 2 = 4 moles sodium.===========================
How many moles of NH3 are produced when 1.2 mol of H2 reacts?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
How many atoms of H are in 2 mol of c8h18?
To determine the number of hydrogen atoms in 2 mol of C8H18, we first need to calculate the molar mass of C8H18. Carbon has a molar mass of approximately 12 g/mol, and hydrogen has a molar mass of approximately 1 g/mol. Therefore, the molar mass of C8H18 is (812) + (181) = 114 g/mol. Next, we use Avogadro's number (6.022 x 10^23) to calculate the number of molecules in 2 mol of C8H18, which is 2 mol * 6.022 x 10^23 molecules/mol. Since there are 18 hydrogen atoms in each molecule of C8H18, the total number of hydrogen atoms in 2 mol of C8H18 is 2 mol * 6.022 x 10^23 molecules/mol * 18 atoms/molecule = 2.17 x 10^25 hydrogen atoms.
0.400mol of octane is allowed to react with 0.800mol of oxygen Which is the limiting reactant?
To determine the limiting reactant, compare the moles of each reactant to the stoichiometry of the balanced. In this case, the balanced equation is: 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O The moles ratio between octane (C8H18) and oxygen (O2) is 2:25. Calculate the ratio for each reactant: Octane: 0.400 mol * (25 mol O2 / 2 mol C8H18) = 5.00 mol O2 needed Oxygen: 0.800 mol O2. Since the actual moles of oxygen available (0.800 mol) are greater than the moles needed for the reaction with octane (5.00 mol), oxygen is in excess and octane is the limiting reactant.
How many moles of O2 are needed to burn 1.50 moles of C8H18?
The balanced equation for the combustion of C8H18 is: C8H18 + 12.5O2 -> 8CO2 + 9H2O From the equation, you need 12.5 moles of O2 to burn 1 mole of C8H18. So, to burn 1.50 moles of C8H18, you would need 1.50 x 12.5 = 18.75 moles of O2.
How many moles of carbon and hydrogen are there in 5 moles of octane?
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
How many moles of water can be produced by burning 325g of octane in excess oxygen?
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
How many moles of ions are produced when 2 mol of Na2CO3 dissociate?
Na2CO32 * 2 = 4 moles sodium.===========================
What is the theoretical yield in grams of CO2 from the reaction of 4.000 moles of C8H18 with 4.000 moles of O2 Chemical equation 2 C8H18 plus 25 O2------ 16 CO2 plus 18 H2O?
Using the stoichiometry of the reaction, the molar ratio of C8H18 to CO2 is 2:16. Therefore, if 4.000 moles of C8H18 are consumed, 16/2 * 4.000 moles of CO2 will be produced. This results in 32.000 moles of CO2, which can be converted to grams using the molar mass of CO2 to get the theoretical yield in grams.
How many moles of NH3 are produced when 1.2 mol of H2 reacts?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
How many moles of KBr will be produced from 14.17 moles of BaBr2?
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
How many moles of KBr will be produced from 4.79 moles of BaBr2?
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
How many grams is 2 moles of Iodine equal to?
mol = mass/Mr rearrange mol x Mr = mass 2 x 126.9g = 253.8g
How many moles of potassium bromide can be produced from the reaction of 2.92 moles of potassium with 1.78 moles of bromine gas?
First write a balanced chemical equation: 2K + Br2 ---> 2KBR Find the limiting reactant by using the moles of each element and determining which one gives you the smallest number of moles of potassium bromide. 2.92 mol K (2 mol KBr/2 mol K)= 2.92 mol KBr 1.78 mol Br2 (2 mol KBR/1 mol Br2)=3.56 mol KBr potassium is your limiting reactant so the max. number of moles of KBr that can be produced is 2.92 mol of KBr
