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How many moles of HCl are required to completely react with .005 moles of NaOH?
Wiki User
∙ 7y ago
Verified answer
Simple equality.
(X L)(2.5 M HCl) = (1.5 L)(5.0 M NaOH)
2.5X = 7.5
X = 3.0 Liters needed
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Wiki User
∙ 12y ago
Wiki User
∙ 12y agoThis sounds like a typical neutralization reaction, so finding the moles of NAOH ( really OH-, but all one to one ) should suffice.
Molarity = moles of solute/liters of solution
or, for our purposes
moles of solute = liters of solution * Molarity
moles of NaOH = 1 liter * 5 M
= 5 moles NaOH
and if reaction is one to one
5 moles of H+ needed for complete neutralization
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Wiki User
∙ 15y agoWell, I'd have thought it would just be 5 moles, wouldn't it?
5HCl + 5NaOH > 5NaCl + 5H2O
or
HCl + NaOH > NaCl + H2O
Wiki User
∙ 7y agoIf you are looking for the reaction to go to completion, then 0.005mol of HCl are required, because the reaction happens in a 1:1 stoichiometric ratio: HCl + NaOH --> NaCl + H2O.
Wiki User
∙ 7y agoThis neutralization reaction is:
HCl + NaOH = NaCl + H2O
For 0,005 moles of sodium hydroxide the necessary amount of hydrogen chloride is also 0,005 moles.
Anonymous
30
How many moles of NaOH are needed to prepare 2 liters of a 2.0 M solution?
4 moles or 160 g NaOH is required for one litre solution.
What volume in mL of a 1.06 M NaOH solution is required to neutralize 11 g of HCl?
Balanced equation. NaOH + HCl -> NaCl + H2O all one to one. find moles HCl. 11 grams HCl (1 mole HCl/36.458 grams ) = 0.3017 moles HCl Moles HCl same as moles NaOH Molarity = moles of solute/Liters of solution 1.06 M NaOH = 0.3017 moles NaOH/liters of solution = 0.2846 Liters this is equal to..... 285 milliliters of NaOH needed
How grams of NaOH is required to nuetralize 100 ml of 1 M H2SO4?
you have 0.1 Moles of sulfuric acid with 0.2 moles of H ions thus requiring 0.2 moles of NaOH - molecular weight = 40 so 40 x 0.2 = 8g NaOH
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
What mass of water forms when 2.75 104 mol NaOH reacts completely?
To make water using NaOH, you can react it with an acid, such as HCl. The reaction isNaOH + HCl ---> NaCl + H2O. 2.75x10^4 moles of NaOH will produce 2.75x10^4 moles of water because the ratio of NaOH to H2O is 1 to 1 (see equation). Thus, the mass of water formed will be2.75x10^4 moles H2O x 18 g/mole = 4.95x10^5 grams of water (495 kg)
How much 1.00 M NaOH is required to react completely with 50.0 ml of 0.5 M CuIISO4?
The answer is 50 mL.
How many moles of MgOH2 will be produced when 30g of NaOH react with MgSO4?
1337
How many moles of NaOH are needed to prepare 2 liters of a 2.0 M solution?
4 moles or 160 g NaOH is required for one litre solution.
What mass of lead(II) nitrate is required to react with 370-g NaOH?
The mass of lead(II) nitrate required to react with 370 g NaOH is 1 531,9 g.
How many liters of naoh are in 1.3 moles of 3.42 m of naoh?
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
What is the mass of 3.42 moles of NaOH?
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH
What volume in mL of a 1.06 M NaOH solution is required to neutralize 11 g of HCl?
Balanced equation. NaOH + HCl -> NaCl + H2O all one to one. find moles HCl. 11 grams HCl (1 mole HCl/36.458 grams ) = 0.3017 moles HCl Moles HCl same as moles NaOH Molarity = moles of solute/Liters of solution 1.06 M NaOH = 0.3017 moles NaOH/liters of solution = 0.2846 Liters this is equal to..... 285 milliliters of NaOH needed
How grams of NaOH is required to nuetralize 100 ml of 1 M H2SO4?
you have 0.1 Moles of sulfuric acid with 0.2 moles of H ions thus requiring 0.2 moles of NaOH - molecular weight = 40 so 40 x 0.2 = 8g NaOH
How many mls of a 2.00m solution of nitric acid are neded to completely react with 15.0g of sodium hydroxide according to the chemical action of hno3 plus naoh nano3 plus h2o?
NaOH = 40 Mwt so 15/40 moles present. This requires 15/40 moles of HNO3 from the above equation. The HNO3 contains 2 moles in 1000 ml and so 1 mole in 500 ml and therefore 500 x 15/40 = 137.5 mls required
How many moles of water are needed to react with 2.5 moles of sodium?
Na + 2H2O -----> H2 + NaOH If you have 2.5 moles water you need 1.25 mol elemental sodium
What is the limiting reagent in a reaction?
The limiting reagent in a reaction is the reactant that runs out first. For example, if you are reacting 10 moles of HCl and 5 moles of NaOH, you will get 5 moles of H20, 5 moles of NaCl, and 5 moles of HCl, because the remaining HCl had nothing to react with. Therefore, the NaOH is the limiting reagent.
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
