85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
1 mole Li = 6.94g Li = 6.022 x 1023 atoms Li 27.0g Li x 6.022 x 1023 atoms Li/6.94g Li = 2.34 x 1024 atoms Li
20,32 g of lithium nitride can be obtained.
AnswerTo find this answer, you need to know the molar mass of the compound. Find the weights of the elements involved, and add them up.Lithium chloride = LiClLithium = 6.94 gramsChlorine = 35.5 gramsLithium chloride = 42.2 gramsThen follow the conversion process:Grams ÷ Molar mass = Moles55.0 grams ÷ 42.4 grams = 1.30 moles LiCl See links below.
3.977 mol
3,00 moles of Li have 18,066422571.10e23 atoms.
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
From the periodic table, lithium has an atomic weight of 6.941. The molar mass of an element is the atomic weight in grams. Therefore, 1 mole Li = 6.941g Li Therefore, moles Li = 15g Li X 1 mole Li/6.941g Li = 2.2 moles Li
0.106 moles Lithium (6.022 X 1023/1 mole Li) = 6.38 X 1022 atoms of Lithium ======================
15g Li * (1mol Li / 6.941g Li) = 2.16 mol Li
For this problem, the atomic mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.2.5 moles H2 × (6.02 × 1023 atoms) = 1.51 × 1024 atoms
4.7 mole Li (6.022 X 10^23/1 mole Li) = 2.8 X 10^24 atoms Li
In LiH the oxidation number of Li (lithium) is 1+ and the oxidation number of H (hydrogen) is 1-
Li: atomic mass 6.941F: atomic mass 18.998Lithium fluoride is made up of these two elements. Its balanced formula is LiF (Li+1F-1). Adding both its atomic masses equals 25.939. Therefore one mole of LiF is equal to 25.939 grams. So, 1.5 moles of LiF is equal to 38.90 grams.
No moles of BaCO3 are found in any amount of Li.
Because 2Li + O2 --> Li2O2 moles Li produces 1 mole Li2O3.04Li + --> 1.52 O2 --> 1.52 Li2O1.52 moles Li2O arw formed.
Lithium hydride, containing Li+ and H- ions.