How many moles of NH3 can be produced from 2.37x10-4 moles of H2?

Answer 1

First we are going to find number of H2 moles form it mass

H2 moles=(2.37*10^-4)/2 = 1.185*10^-4moles

Since 3 moles of H2 makes 2 moles of NH3

then by using this ration, we can find number of moles in NH3

NH3 moles= (2 * 1.185*10^-4)/3 = 0.79*10^-4 moles

Finally, we find number of NH3 molecules by multiplying the number of moles with (6.022*10^23).

#NH3 molecules = (0.79*10^-4) *(6.022*10^23)

=4.75 * 10^19 molecules of NH3

Good luck

Enas

Answer 2

The balanced chemical equation for the reaction is:

3H2 + N2 -> 2NH3

From the equation, we can see that 3 moles of H2 are required to produce 2 moles of NH3. Therefore, the number of moles of NH3 that can be produced from 2.37x10-4 moles of H2 is 2.37x10-4 mol x (2 mol NH3 / 3 mol H2) = 1.58x10-4 moles of NH3.

Answer 3

Balanced equation.

N2 + 3H2 --> 2NH3

1.4 moles H2 (2 moles NH3/3 moles H2)

= 0.93 moles NH3 produced

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Answer 4

3.19*10^24