3.00 grams NaHCO3 (1 mole/84.008 grams)
= 0.0357 moles of sodium bicarbonate
There are 1.5 moles water in 27 grams
No. of moles=given mass/gram molecular mass =16/16 =1
A sample of 56,4 of magnesium is equal to 2,32 moles.
.998 moles
0.1mol
Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3
The same amount.
There are 1.5 moles water in 27 grams
the mole is 30 g.
The answer is 6,31 moles Ag.
NaHCO3 ----> H2O Mass 2.10g 0.045g RAM 84 g/moles 18 g/moles number of moles 0.025moles 0.025moles
No. of moles=given mass/gram molecular mass =16/16 =1
80,0 moles of CO2is equal to 3 520,8 g.
1 mole=6.02*1023 molecules or atoms5.23 moles=6.02*1023 * 5.23= {[(3.14846*1024molecules)]}
A sample of 56,4 of magnesium is equal to 2,32 moles.
.998 moles