.998 moles
0.09375 moles. Calcium's molar mass is 40, so mass/molar mass (3.75/40) gives 0.09375.
The chemical formula for the compound calcium chloride is CaCl2. The atomic mass of CaCl2 is 40.1 + 2(35.5) = 111.1Amount of CaCl2 = mass of pure sample/molar mass = 0.2/111.1 = 0.00180mol There are 0.00180 moles of CaCl2 in a 0.2 gram pure sample.
There are 3.275 moles of calcium in 131 grams as relative atomic mass of calcium is 40. Therefore there are 1.972 x 1024 atoms.
Calcium carbonate has the formula CaCO3 . Refer to the Periodic Table for atomic masses. 1 x Ca = 1 x 40 = 40 1 X C = 1 x 12 = 12 3 x O = 3 x 16 = 48 40 +12 +48 = 100 (The Mr : Reltive Molecular mass of CaCO3) Next use the wquation Moles = mass(g) / Mr Substituting Moles = 10.10 g / 100 moles = 0.101 moles.
1mol Ca = 40 gCa 45.8g/40g = 1.145 mol Ca
0.09375 moles. Calcium's molar mass is 40, so mass/molar mass (3.75/40) gives 0.09375.
The chemical formula for the compound calcium chloride is CaCl2. The atomic mass of CaCl2 is 40.1 + 2(35.5) = 111.1Amount of CaCl2 = mass of pure sample/molar mass = 0.2/111.1 = 0.00180mol There are 0.00180 moles of CaCl2 in a 0.2 gram pure sample.
There are 3.275 moles of calcium in 131 grams as relative atomic mass of calcium is 40. Therefore there are 1.972 x 1024 atoms.
Calcium carbonate has the formula CaCO3 . Refer to the Periodic Table for atomic masses. 1 x Ca = 1 x 40 = 40 1 X C = 1 x 12 = 12 3 x O = 3 x 16 = 48 40 +12 +48 = 100 (The Mr : Reltive Molecular mass of CaCO3) Next use the wquation Moles = mass(g) / Mr Substituting Moles = 10.10 g / 100 moles = 0.101 moles.
40 g of Ca = 1 mole So 808 g of Ca = 20.2 mole
1mol Ca = 40 gCa 45.8g/40g = 1.145 mol Ca
To find the molar mass of Calcium, you have to multiply Calcium's atomic number by moles. The equation is: (6.022x10^23)x 40.08= 2.4136176x10^25
Atomic Weight of Calcium = 40 Atomic Weight of Chlorine = 35.5 Therefore, 1 mole of CaCl2 => 40 + 2 (35.5) = 111 g 0.74 moles of CaCl2 => 0.74 (111) = 82.14 g
The formula of calcium carbonate is CaCO3. Therefore, its molar mass is the sum of the atomic masses of calcium and carbon and three times the atomic mass of oxygen: 40.078 + 12.011 + 3(15.999) = 100.086. The number of moles in 10 g is 10 divided by the molar mass = 0.10 moles, to the number of significant digits justified by "10 g".
First calculate the moles of Calcium Moles(Ca) = 169g/ 40 (Atomic Mass) moles(Ca) = 4.225 moles. Remember the Avogdro No. which is the number of ato,ms/molecules in one mole. Hence 6.022 x 10^*23) = 1 mole. We have 4.225 moles So multiplying 4.225 X 6.022 x 10^(23) = 2.54 x 10^(24) atoms)
no of mol = mass/molar mass = 72/ (40+32+16x4) = 72/136 = 0.529 mol (3.s.f)
Use the equationmol = mass / RFM (or RAM)mol = 37 / (40 + 16x2 + 1x2)mol = 37 / 74mol = 0.5