Calcium carbonate has the formula CaCO3 .
Refer to the Periodic Table for atomic masses.
1 x Ca = 1 x 40 = 40
1 X C = 1 x 12 = 12
3 x O = 3 x 16 = 48
40 +12 +48 = 100 (The Mr : Reltive Molecular mass of CaCO3)
Next use the wquation
Moles = mass(g) / Mr
Substituting
Moles = 10.10 g / 100
moles = 0.101 moles.
The answer is 0,1009 moles.
2,8 moles of calcium carbonate have 240,208 g.
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
i am asking the same thing
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
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2,8 moles of calcium carbonate have 240,208 g.
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
.06 moles
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
i am asking the same thing
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
it will consume my dick
No. of moles=wt. of substance/molecular wt. hence, wt. of substance= 2.38*100=238
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen