For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams
110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3
n(NaHCO3)=?
n(X)=m(X)/M(X)
m(NaHCO3)=2,10kg=2100g
M(NaHCO3)= [Ar(Na)+Ar(H)+Ar(C)+3*Ar(O)]g/mol
M(NaHCO3)=(22.99+1.008+12.01+3*16.00)g/mol
M(NaHCO3)=84.008 g/mol
n(NaHCO3)=2100g:84.008g/mol=25mol
There are 25 moles of NaHCO3 in 2.1kg of NaHCO3.
Given mass divided by formula mass is the no of moles so moles are 0.0238.
The answer is 1,31 moles.
The answer is: 0,0238 moles.
4 mol over 0.800 kg
The three main ways are: molarity (M) = moles solute/liters solution; molality (m) = moles solute/kilograms solvent; mole fraction = moles 1 component/total moles all components. There's also percent by volume, percent by mass, and normality.
One pound is about 0.453 kg
175 kg is 386 pounds.
1.54 kg.
1 kg of difluorodichloromethane is equivalent to 8,27 moles.
12,4439 kg of gold contain 63,177 moles.
2.70 m = 2.70 moles/kg solvent3250 g solvent = 3.25 kg solvent2.70 moles/kg x 3.25 kg = 8.775 moles NaNO3 = 8.78 moles NaNO3 (3 significant figures)
1 lbs is equal to 0.45359237 kg. So, 210 lbs is about 95 kg. accurate 95.34 kg
The answer is 30,151 kg.
15kg is 15000g. 15000/58.12 = 258.087 moles.
1 kg NaCl contain 17,112 moles.
(1kg C2H6O2 )(1000g/1kg)(1mol/62g) = 16.1 moles
210 kg squared equals 44100 kg.
Approx 210.
This depends on the specific element or compound.
5.00 kg of Cu is equivalent to 78,68 moles.