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For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams

110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3

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15y ago
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13y ago

n(NaHCO3)=?

n(X)=m(X)/M(X)

m(NaHCO3)=2,10kg=2100g

M(NaHCO3)= [Ar(Na)+Ar(H)+Ar(C)+3*Ar(O)]g/mol

M(NaHCO3)=(22.99+1.008+12.01+3*16.00)g/mol

M(NaHCO3)=84.008 g/mol

n(NaHCO3)=2100g:84.008g/mol=25mol

There are 25 moles of NaHCO3 in 2.1kg of NaHCO3.

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14y ago

Given mass divided by formula mass is the no of moles so moles are 0.0238.

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9y ago

The answer is 1,31 moles.

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11y ago

The answer is: 0,0238 moles.

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Q: How many moles are in 2.10 kg of NaHCO3?
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