The chemical formula of the anhydrous copper(II) sulfate is CuSO4. The molar mass is 159,609. The percentage of oxygen is 40,25 %, or 64,245 g.
64,245 g oxygen (O2) is equal to cca. 2 moles.
5 mole copper (6.022 X 1023/1 mole Cu) = 3 X 1024 atoms of copper -----------------------------------
Only one mole of copper.
2.95 mole H2O (2 moles H/1 mole H2O) = 5.90 moles hydrogen ------------------------------
1 mole
I mole of copper hydroxide is 98g (64 + 16 + 1 + 16 + 1) So 68g is 68/98 moles = 0.694g I have used 64 for the ram of copper. Your list might use a slightly different value, so substitute that.
5 mole copper (6.022 X 1023/1 mole Cu) = 3 X 1024 atoms of copper -----------------------------------
5,25 moles (in anhydrous sodium sulphate)
1.20x10^24 atoms x 1 mole/6.02x10^23 atoms = 1.99 moles
Only one mole of copper.
6.02 X 1023 particles per mole X .75 moles = 4.52 X 1023 molecules.
One mole of oxigen (O2-the diatomic molecule) is needed for 127,092 g copper to form CuO.
From the density and volume, the mass of this amount of copper is 8.96 grams. There are 63.546 grams in 1 mole of copper, so this is 0.141 moles. There are 6.023 x 10²³ atoms in 1 mole. Multiply this by 0.141 moles = 8.492 x 10²² atoms.
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
2.95 mole H2O (2 moles H/1 mole H2O) = 5.90 moles hydrogen ------------------------------
i havent got an elements table in front of me but here is how you do it: figure out how many moles is 2.9 grams of copper by using molecular wieght, then simply multiply so: No of moles* No of atoms in one mole* number of electrons in one atom of copper (which is the same as the No of protons...)
1 mole of Copper has a mass of 63.546 g. So, 14.5 moles will be 14.5 times that amount. Do the math.
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen