To find the number of copper atoms in a 94.5 g sample, first determine the molar mass of copper, which is approximately 63.55 g/mol. Using the formula ( \text{moles} = \frac{\text{mass}}{\text{molar mass}} ), we can calculate the moles of copper: ( \frac{94.5 , \text{g}}{63.55 , \text{g/mol}} \approx 1.49 , \text{moles} ). Since one mole contains Avogadro's number of atoms ((6.022 \times 10^{23}) atoms/mole), the total number of copper atoms is ( 1.49 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 8.96 \times 10^{23} ) atoms.
Only one mole of copper.
4.0 moles Cu (6.022 X 1023/1 mole Cu) = 2.4 X 1024 atoms of copper ====================
The molar mass of copper is 63.5 g/mol. Using this, you can calculate that in a 12.0 gram sample of copper, there are approximately 0.189 moles of copper. Since 1 mole of a substance contains 6.02 x 10^23 atoms (Avogadro's number), the number of atoms in 0.189 moles of copper would be around 1.14 x 10^23 atoms.
The answer is 6,31 moles Ag.
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
Approx. 9.1024 atoms.
Copper phosphate has the chemical formula Cu3(PO4)2. To determine the number of atoms, you need to add up the atoms in each element present. In this case, there are 3 copper atoms, 2 phosphorus atoms, and 8 oxygen atoms, totaling 13 atoms in copper phosphate.
To find the number of moles of copper, we first need to calculate the total mass of copper in the sample. Copper has an atomic mass of 63.55 g/mol. The total mass of the sample is 1.20 g x 1024 atoms = 1228.8 g. Next, we convert this mass to moles by dividing by the atomic mass of copper: 1228.8 g / 63.55 g/mol = 19.36 moles of copper.
Copper is an element. You can have a single atom or many atoms and it's still copper.
Only one mole of copper.
The molar mass of copper is approximately 63.5 g. To find how many of these are in our sample we must divide.0.0159/63.5 = 2.5 x 10 ^ -4 = 0.00025 moles. Each mole contains the Avogadro number of atoms, i.e. 6.023 x 10 ^ 23, so in total we have 0.00025x 6.023 x 10 ^ 23 = 1.51 x 10 ^ 20 atoms approximately.
4.0 moles Cu (6.022 X 1023/1 mole Cu) = 2.4 X 1024 atoms of copper ====================
The answer is 47,128 x 1023 atoms.
There are no "atoms in an element," but rather atoms OF an element. If you are trying to find the number of atoms in a sample of a pure element you divide its weight by its molar mass and then multiply by 6.022 x 10^23 to get the answer in atoms. The answer options are 2,3, or 4.
To find out how many atoms are present in calcium, you would need to use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Simply divide the mass of the calcium sample by the atomic mass of calcium (40.08 g/mol) and then multiply by Avogadro's number to determine the number of atoms present.
To find the number of atoms in 6.35 g of copper, you first need to determine the number of moles of copper present by dividing the mass of copper by its molar mass (63.55 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms in that number of moles.
To calculate the number of atoms present in 6.81g of copper, you would first need to determine the number of moles of copper using its molar mass. Copper has a molar mass of 63.55 g/mol. Dividing 6.81g by the molar mass of copper gives approximately 0.107 moles. Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of atoms, which is about 6.45 x 10^22 atoms.