Calcium nitrate has 9 atoms.
7.92 grams calcium fluoride (1 mole CaF2/78.08 grams)(6.022 X 1023/1 mole CaF2) = 6.11 X 1022 atoms of calcium fluoride --------------------------------------------------
The formula unit for calcium nitride is Ca3N2. That would be 3 atoms of calcium and 2 atoms of nitrogen, for a total of 5 atoms in a formula unit.
The answer is 28,0987.1023 atoms.
According to the law of conservation of mass how many atoms of calcium can react to produce more calcium?
61,5 g calcium contain 9,241.10e23 atoms.
Calcium nitrate has 9 atoms.
there are 20 atoms in calcium
Ca3 (PO4)2 has 13 atoms in the molecule.
7.92 grams calcium fluoride (1 mole CaF2/78.08 grams)(6.022 X 1023/1 mole CaF2) = 6.11 X 1022 atoms of calcium fluoride --------------------------------------------------
First you need to find how many moles of calcium that is. Since 1 mole of calcium is 40.078g you need to divide 60.8g by how much is one mole (60.8 / 40.078 = 1.517 moles). Once you know how many moles you have (1.517) you can find how many particles there are. There are 6.02 *10^23 atoms in one mole (Avagadro's number), so your final answer will be, 6.02*10^23 x 1.517 = 9.132 * 10^23
Calcium sulfide (CaS) has two atoms.
149 g of calcium contain 22,39.10e23 atoms.
Calcium hypochlorite - Ca(ClO)2 has 5 atoms.
Calcium iodide (CaI2) has two iodine atoms and one calcium atom.
The formula unit for calcium nitride is Ca3N2. That would be 3 atoms of calcium and 2 atoms of nitrogen, for a total of 5 atoms in a formula unit.
The answer is 28,0987.1023 atoms.