Calcium Nitrtae is Ca(NO3)2 and so there are two moles of nitrate per mole of calcium nitrate. Thus there are 2 x 2.50 = 5.0 moles of nitrate present.
Hydrogen nitrate has a mass of 63.01 g/mol. In order to find the number of moles you divide the grams by the molar mass. 250/63.01 = 3.96 mol.
This solution contain 0,3 mol of sodium chloride.
Molar mass of KCl = 39 g/mol (K) + 35.5 g/mol (Cl) = 74.5 g/mol. A 0.5 M solution is required (0.5 mol/L or 0.5 moles per litre). 0.5 moles of KCl is 0.5 mol x 74.5 g/mol = 37.25 g. Dissolving this 37.25 g of KCl in a litre of water would give a 0.5 M solution. If 1 L or 1000 mL of 0.5 M solution contains 0.5 moles then 1 mL of the same concentration solution would contain 0.5/1000 moles and 250 mL would contain 250 x 0.5/1000 moles = 0.125 moles. 0.125 moles of KCl is 0.125 mol x 74.5 g/mol = 9.31 g.
The solution has a total mass of 30 + 250 = 380 g. The mass percent of calcium chloride in this solution is 100(30/380) = 7.9 %, to the justified number of significant digits.
n=c/v n=3M/.25L n=12 mol m=Mxn m=58.443 g/mol x 12 mol m=701.3 g n= mol c=concentration v=volume m=mass M= molar mass Tylerops: I don't agree with this answer. Molarity is defined as Moles/Liters. In other words Molarity is the concentration of a solution. In the above n= Concentration / Liters. That is equal to saying Moles=(Moles/liters)/ Liters. In the above question the concentration is (3 moles/ liter), or 3M. Plus, how can it be possible to have 12 moles in 250ml when you only have 3 moles in each liter of the original solution? Correct ANSWER: 3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles. 58.443g/molNaCl x .75 moles = FINAL ANSWER 43.83225g NaCl, Sig Fig, 43.83gNaCl
Hydrogen nitrate has a mass of 63.01 g/mol. In order to find the number of moles you divide the grams by the molar mass. 250/63.01 = 3.96 mol.
To find the number of moles in 250 g of CaCO3, divide the given mass by the molar mass of CaCO3. The molar mass of CaCO3 is 100.09 g/mol. So, 250 g รท 100.09 g/mol โ 2.50 moles of CaCO3.
250 g iron (III) oxide is equal to 1,565 moles.
To calculate the amount of calcium chloride to add, you first need to determine the number of moles required using the formula Molarity = moles/volume. In this case, 0.236 M = moles/0.25 L. This gives you 0.059 moles of calcium chloride needed. Since calcium chloride has a molar mass of 110.98 g/mol, you will need 6.58 grams of calcium chloride to make a 0.236 M solution in 250 mL of water.
1 mole in 250 ml and 4 moles in 1 liter or 1000 mls
1 mole of anything is 6.022 x 1023 atoms or molecules of that substance. Thus, 2500 atoms of a substance is about 4.151 x 10-21 moles of that substance.
To determine the number of moles of CaCl2 in a solution, you need to know the concentration of the solution in mol/L. Without this information, it is not possible to calculate the number of moles of CaCl2 in the given volume of 250 ml.
Answer=408.47 250Li2SO4/109.89Li2SO4/2x4x89.774 4LiNO3
Ther answer is none! ammonium bromide is made from hydrogen bromide and ammonia NH3 + HBr = NH4Br i mole of each makes 1mole of ammonium salt.
Will have to make some assumptions with the little info given. Solid sucrose is 1.587 g/ml in density and has a mass of 342.30 grams/mole Density = grams/milliliters 1.587 g/ml = grams/250 ml = 396.75 grams/342.30 grams = 1.159 moles of sucrose
2 x Avogadro's number. It should be noted that 2 moles of VW Beetles would have a mass over 250 times greater than that of the entire Earth.
To prepare a 0.100 M solution of trinitrotoluene in 250 ml of solvent, you need 0.025 moles of trinitrotoluene. The molar mass of trinitrotoluene is 227.14 g/mol, so you would need 5.68 grams of trinitrotoluene to make the solution.