Argon has an Atomic Mass of 39.948. Therefore, it has 39.948 grams per mol.
Ar(mol) = 14.5 g / 39.948 g/mol
Ar(mol) = 0.363 mol
moles = mass in grams / atomic weight So moles in 37.9 g or argon = 37.9 / 39.948 = 0.948 moles
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
The mass number of Argon is 39.948 so it is 119.98/39.948=3.0034 moles of Argon in 119.98 g of Argon or approximately 3 moles of Argon is in 119.98 g this gas.
the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles
Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.
moles = mass in grams / atomic weight So moles in 37.9 g or argon = 37.9 / 39.948 = 0.948 moles
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
The mass number of Argon is 39.948 so it is 119.98/39.948=3.0034 moles of Argon in 119.98 g of Argon or approximately 3 moles of Argon is in 119.98 g this gas.
the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles
Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.
Moles = mass in grams / atomic weight So moles in 15.01 g of Ar = 15.01 / 39.948 = 0.38 moles
1 mole of argon weighs 39.948 g. So 7 moles will weigh 279.636 g
From the Periodic Table, Argon has an atomic weight of 39.948. One mole of any element is equal to its atomic weight in grams. So 1 mole of Ar = 39.948g of Ar. Using that equality, you do the following calculation to find the number of moles of Ar in 22g of Ar: 22g Ar X 1mol Ar/39.948g Ar = 0.55mol Ar
3,80 g Zn have 0,058 moles.
The formula is: number of moles = g Be/9,012.
Answer: 145 lb = 65,770.893 g
The answer is 0,253 moles.