Divide that number by Avogadro's number: 3.968x10(23) / 6.02x10(23) = 0.659mol Mg, which would be about 16g.
The answer is 0,6589 moles.
8,23.1023 atoms Mg is equivalent to 1,366 moles.
This is equivalent to 1,4 moles.
2.01x10^22 atoms x 1 mole/6.02x10^23 atoms = 0.0334 moles
1.203mol
1 mole of any element contain 6,022 140 857.1023 atoms (Avogadro number).2,5 moles of magnesium contain 15,0553521425.1023.
8,23.1023 atoms Mg is equivalent to 1,366 moles.
This is equivalent to 1,4 moles.
1 mole Mg = 6.022 x 1023 atoms Mg 12.04 x 1023 atoms Mg x 1mol Mg/6.022 x 1023 atoms Mg = 1.999 moles Mg
2.01x10^22 atoms x 1 mole/6.02x10^23 atoms = 0.0334 moles
6,02214129.10ex.23---------------1 mol458.10ex.23---------------------------xx = 76,o5 moles Mg
1.203mol
5.1 moles Mg (6.022 X 1023/1 mole Mg) = 3.1 X 1024 atoms of magnesium ========================
1 mole of any element contain 6,022 140 857.1023 atoms (Avogadro number).2,5 moles of magnesium contain 15,0553521425.1023.
17.54 mg
There are 18.9 moles in 225.8 mg. This is a math problem.
First you need to find the atomic mass of magnesium, 24.3 grams.Then you can do a simple conversion:Grams ÷ Atomic mass = Moles7.5 grams ÷ 24.3 grams = 0.309 moles Mg
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium