126 grams calcium (1 mole Ca/40.08 grams)
= 3.14 moles of calcium
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1mol Ca = 40 gCa 45.8g/40g = 1.145 mol Ca
The answer is 0,07 moles Ca(OH)2.
77.4 gCa x 1 Mole Ca/40.08 gCa = 1.931 mol Ca
0.5 = moles calcium nitrate / 3 L 0.1667 moles Ca(NO3)2 0.1667 * 148 = 24.7g Ca(NO3)2
25.0 moles Ca x 6.02x10^23 atoms/mole = 1.50x10^25 atoms
425 g calcium (Ca) is equal to 10,604 moles.
3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============
Calcium, Ca has atomic mass of 40.1Amount of Ca = 16.5/40.1 = 0.411molThere are 0.411 moles of calcium in a 16.5 gram sample.
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
978 g calcium contain 24,4 moles.
156 g calcium is equivalent to 3,89 moles.
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
0,688 g calcium is equivalent to 0,017 moles.
Calcium Nitrtae is Ca(NO3)2 and so there are two moles of nitrate per mole of calcium nitrate. Thus there are 2 x 2.50 = 5.0 moles of nitrate present.
Ca (NO3)2 So the number of Ca atoms will just be Avogadro's constant, L
Ca!