.913 moles
2Ca + O2 --> 2CaO The molar mass of Calcium is 40g/mol. 36.5g/40g gives you 0.9125 moles of Calcium. The moles of calcium are equivalent to the moles of Calcium oxide. The answer is 0.9125 moles of calcium oxide. Correct me if I am wrong.
Calcium contains only one atom per molecule, while oxygen contains two. The usual reaction product from a reaction between calcium and oxygen has the formula CaO and therefore contains one atom of each element per molecule. 4 moles of oxygen provides 8 moles of oxygen atoms, so that under the conditions given, calcium is the limiting reactant, and 6.55 moles of calcium oxide will be formed.
1400 grams
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen
2Ca + O2 --> 2CaO The molar mass of Calcium is 40g/mol. 36.5g/40g gives you 0.9125 moles of Calcium. The moles of calcium are equivalent to the moles of Calcium oxide. The answer is 0.9125 moles of calcium oxide. Correct me if I am wrong.
Calcium contains only one atom per molecule, while oxygen contains two. The usual reaction product from a reaction between calcium and oxygen has the formula CaO and therefore contains one atom of each element per molecule. 4 moles of oxygen provides 8 moles of oxygen atoms, so that under the conditions given, calcium is the limiting reactant, and 6.55 moles of calcium oxide will be formed.
4.8/16 moles of oxygen atoms converts to 1.6/16 moles of ozone molecules.
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
1400 grams
Suppose we react 6.00 moles calcium with 4.00 mol oxygen gas. Determine the number of moles of oxygen left over after the reaction is complete.
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
6 moles
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3