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moles = mass (g) divided by the molecular weight (g/mol)
moles = 100g/12.01
Wiki User
∙ 15y ago
Wiki User
∙ 15y agoIt all depends on what chemical you're working with. If you have hydrogen, you need 100 moles to make 100 grams. Uranium 235? Less than half a mole.
Wiki User
∙ 14y agoCarbon has an Atomic Mass of 12, while oxygen has an atomic mass of 16, the molecular weight of CO2 would therefore be 44 grams per mole, so about 2.3 moles roughly
Wiki User
∙ 8y ago100 molecules of CO2 equals 0,166.10e-21 moles.
Wiki User
∙ 6y ago100 g of carbon contain 50,1427.1023 atoms.
Wiki User
∙ 12y agoThe answer is 50,14.1023 atoms.
Wiki User
∙ 8y ago1 g carbon equals 0,083 moles.
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How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
First a balanced chemical equation is needed.CH4 + 2O2 -> CO2 + 2H2OThere is a 1:1 ratio of moles between methane and carbon dioxide so the amount of moles of methane used is the exact number of moles of carbon dioxide yielded.To determine the number of moles of methane we take the amount used and divide by methane's mass which is about 16.04 g/mol.100g/ 16.04g/mol=6.234moles of methane.6.234 moles of methane are used and 6.234 moles of carbon dioxide are produced.
A compound is 80.0 carbon and 20.0 hydrogen by mass Assume a 100g sample of this compound How many grams of each element are in this sample?
Mass of C= 80.0 g Mass of H =20.0 g
If 12.5 grams of the original sample of cesium-137 remained after 90.69 years what was the mass of the original sample?
100g
What is the half life of a radioisotope if a 100g sample becomes 25g after 18 years?
9 years
A hydrate is found to have the following percent composition 48.8 percent MgSO4 and 51.2 percent H2O What is the formula and name for this hydrate?
48.8 g MgSO4 & 51.2 g H2O Convert the mass into moles by dividing molar mass for each. Then obtain a ratio of moles of water over moles of Magnesium Sulfate, and you would get 7. MgSO4 . 7H2O would read as Magnesium Sulfate Heptahydrate.
How many moles Fe are in a sample of Fe2O3 that contains 100g O?
100 grams oxygen (1 mole O/16 grams)(2 mole Fe/3 mole O) = 4.17 moles iron --------------------------
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
First a balanced chemical equation is needed.CH4 + 2O2 -> CO2 + 2H2OThere is a 1:1 ratio of moles between methane and carbon dioxide so the amount of moles of methane used is the exact number of moles of carbon dioxide yielded.To determine the number of moles of methane we take the amount used and divide by methane's mass which is about 16.04 g/mol.100g/ 16.04g/mol=6.234moles of methane.6.234 moles of methane are used and 6.234 moles of carbon dioxide are produced.
A compound is 80.0 carbon and 20.0 hydrogen by mass Assume a 100g sample of this compound How many grams of each element are in this sample?
Mass of C= 80.0 g Mass of H =20.0 g
What is the cost of carbon?
100g=$2.40
How many grams of calcium carbonate are needed to produce 49.0 L of carbon dioxide at STP?
n=(1atm)(49L)/(0.0821)(273.15)=2.19 moles2.19 moles x 44g of CO2 =96.36g of CO22.19 moles x 100g of CaCO3= 219g of CaCO3
If 12.5 grams of the original sample of cesium-137 remained after 90.69 years what was the mass of the original sample?
100g
What is the half life of a radioisotope if a 100g sample becomes 25g after 18 years?
9 years
What is the half life of a radioisotope if a 100g sample becomes 50 g after 20 years?
20 years (APEX)
A hydrate is found to have the following percent composition 48.8 percent MgSO4 and 51.2 percent H2O What is the formula and name for this hydrate?
48.8 g MgSO4 & 51.2 g H2O Convert the mass into moles by dividing molar mass for each. Then obtain a ratio of moles of water over moles of Magnesium Sulfate, and you would get 7. MgSO4 . 7H2O would read as Magnesium Sulfate Heptahydrate.
How many grams of calcium carbonate are required to prepare 50.0 g of calcium oxide?
This is a mass stoichiometry problem. Start with the balanced equation: CaCO3 --> CaO + CO2. Do a conversion from 50g CaO to moles: 56g/1mol=50g/x, x=.9 moles. The equation is balanced as written, with all coefficients understood to be 1. So: .9 moles CaO means .9 moles CaCO3. Do another conversion from moles to grams: 100g/1mol=x/.9 moles. Solve for x to get 90 grams. (56g=molar mass of calcium oxide; 100g=molar mass of calcium carbonate.)
How many atoms of carbon are in one cookie?
assuming you know the exact chemical composition of a cookie (which I don't) you can find this using Avogadro's number. Lets say the cookie is composed completely of glucose (not a very tasty or nice looking cookie). The molecular formula for glucose is C6H12O6, therefor for every glucose molecule in that cookie there is 6 carbon atoms. Lets say we have a 100g cookie composed completely of glucose, we can find the number of moles of glucose by dividing the mass of the cookie (taken to be enitrely made of glucose) by its molar mass (approximately 180 g/mol, which can easily be calculated from the periodic table). So #moles=100g/180g/mol = approx 0.556 moles of glucose are in that gross cookie. Using Avogadros number we know that there is 6.022x10^23 particles per mole, so # molecules of glucose in 0.556 moles = (6.022x10^23/mol)(0.556mol)= 3.35x10^23 molecules of glucose in the cookie. But for each molecule of glucose there is 6 carbon atoms so 6(3.35x10^23)= 2.01x10^24 carbon atoms.
What is the molarity of 0.1 normal KMnO4?
The formula mass of KMnO4 is 158.0Amount of KMnO4 = mass of sample / molar mass = 100/158.0 = 0.633 molThere are 0.633 moles in 100g of potassium permanganate.
