stp= 22.4 dm3, 1L = 1 dm3
1mole ---> 22.4dm3
xmole ---> 45dm3
45/22.4 = 2.001 moles
Using idea gas law equation,
There is 1.21 moles of gas
2.23
0.48 liters at STP (standard temperature and pressure)
The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
The equivalent in moles is 6,03.
4.7 times the ambient air pressure which is ? Need more data...
According to the ideal gas law, all gases occupy about 22.4 liters per moleof space at standard temperature and pressure, so 22.4x2.56=57.34 liters.
140 kilopascals.
240
If the volume is reduced, and all else remains the same, then the pressure will increase by a factor of 2, or it will double.
If the volume is reduced, and all else remains the same, then the pressure will increase by a factor of 2, or it will double.
3,394 cubic inches can contain up to about 55.62 liters of water.
A piston has an external pressure of 10.0 . How much work has been done if the cylinder goes from a volume of 0.170 liters to 0.460 liters.
The pressure is 20,68 at.
54 liters at STP (standard temperature and pressure)
0.48 liters at STP (standard temperature and pressure)
you multiply them the change it to liters
The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
It means there are 22.4 liters of an "ideal" gas at STP (standard temperature and pressure), implying that temperature = 273.15 K and pressure = 1 atm.