How many moles of hydrogen are in 3 moles of ammonia NH3?
9 moles H atoms
2,00 moles of ammonia (NH3) have 3 moles of hydrogen.
0.6 moles of N2 produce 1.2 moles of NH3
2N + 3H2 -> 2NH3 18 moles H2 (2 moles NH3/3 moles H2) = 12 mole ammonia
NH3 is balanced at 1:3, so in 3 moles NH3 there are 3*3 = 9 moles H atoms
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
There are two elements that make up Ammonia (NH3) … One mole of Nitrogen (N) plus three moles of Hydrogen (H) react to produce one mole of Ammonia (NH3)
How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
3H2 + N2 <------> 2NH3 is the balanced equation for Hydrogen and Nitrogen making ammonia. 3 moles of H2 produces two moles of ammonia and thus to make 6 moles requires 9 moles of Hydrogen.
N2 + 3H2 ---> 2NH3 so 3 moles of hydrogen produces 2 moles of ammonia. Therefore with 6 moles of hydrogen available, 4 moles of ammonia only are possible as the hydrogen is the yield limiting material.
Ammonia is formed by the following: N2 + 3H2 --> 2NH3 (1) Convert grams of ammonia to moles of ammonia using its molecular weight (17 g /mole) 10.14 g NH3 / (17 g NH3/mole NH3) = 0.597 moles NH3 (2) Now, using the reaction from above we see that for every mole of ammonia formed that 3 moles of hydrogen gas are used. Assuming that the reaction is in stoichemtric proportions you can figure out… Read More
N2 + 3H2 ---> 2NH3 so 3 moles of Hydrogen produces 2 moles of ammonia. Thus 1.8 moles will produce 1.8/3 x 2 = 1.2 moles of ammonia.
N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3
The balanced equation for the formation of NH3 is N2 + 3 H2 --> 2 NH3. 13.64 grams of ammonia is equal to .801 moles. Then 1.2015 moles of hydrogen are needed, or 2.42 grams.
There are three hydrogens in ammonia. NH3
Enough nitrogen means equal or in excess, so..... 3H2 + N2 -> 2NH3 7.5 mole hydrogen gas (2 mole NH3/3 moles H2) = 5.0 mole ammonia made ----------------------------------
How many moles of ammonium bromide can be produced from 250 moles of bromine and 600 moles of ammonia?
Ther answer is none! ammonium bromide is made from hydrogen bromide and ammonia NH3 + HBr = NH4Br i mole of each makes 1mole of ammonium salt.
Ammonia = NH3 Molecular mass = 16.0 Formula of grams to moles: grams / molecular mass = moles 170,000 g / (16.0) = 10,600 moles NH3 Note that the answer is with three significant digits
(2.50 moles NH3) (17.04 grams NH3/moles NH3) = 42.6 grams of NH3 17.04 grams is the molecular weight of ammonia
The formula for ammonia is NH3, so an ammonia molecule has three hydrogen atoms.
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023) = 0.132 moles ammonia =================
How many moles of ammonia gas are produced by the reaction of 3 mole of nitrogen gas with excess hydrogen gas N2 H2 ---- NH3?
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
Ammonia has the chemical formula NH3, and thus there are three hydrogen atoms in a molecule of ammonia.
I mole of ammonia is 17g, so 4.5 moles are 76.5g
Ammonia is NH3. It has three hydrogens per molecule.
Molar mass of ammonia is 17 g. Therefore in 12 x 10.3 g of ammonia there will be 7.27 moles of ammonia.
O,8 moles of ammonia are produced.
Well this a difficult question. It depends what you are making, there are over 20 binary compoundsno nitrogen and hydrogen. The best known of which is ammonia, NH3 but others include hydrazine, N2H4 triazine N3H5. As an example in the reaction of N2 with H2 to form ammonia. N2 + 3H2 -> 2NH3 If you take two moles of nitrogen then you will need 6 moles of hydrogen.
88.25 g Hydrogen
Ammonia is NH3 so 1 nitrogen and 3 hydrogen
a mole of nitrogen gas, three moles of hydrogen gas, and two moles of ammonia.
1 g of ammonia (NH3) is equal to 0,059 mol.
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
Ammonia (NH3) contain nitrogen and hydrogen.
34 grams of Ammonia
The mass of ammonia will be 95,03 g.
1 mole NH3 (3 mole H/1 mole NH3) = 3 mole hydrogen atoms
Ammonia is NH3: so three.
Molar mass of ammonia = (14.01 + 3.03) (Molar mass of nitrogen + 3 times molar mass of hydrogen, as chemical formula of ammonia is NH3). Molar mass= 17.04 Molar mass x moles = mass 17.04 x 3 = 51.12 Mass of 3 moles of ammonia is 51.12g.
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams 100 grams NH3 / (16.0 grams) = 6.25 moles NH3
Results for Calculate The Amount In Moles Of Molecules For Each Substance. A) A Sample Of Ammonia NH3(g) Containing 8.1x1020 Atoms Of Hydrogen?
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
33 moles or nitrogen and 9 moles of hydrogen are needed.
NH3 Looks like three atoms of hydrogen are in a molecule of ammonia.
No. Ammonia, NH3, is a compound of nitrogen and hydrogen.
170 kg = 170,000g NH3 = 170,000g / 17.0g/molNH3 = [10,000 molNH3] * 3moleH2 / 2moleNH3 = 15,000 mole H2 needed to produce 170 kg NH3
150 grams NH3 (1 mole NH3/17.034 grams)(3 mole H/1 mole NH3)(1.008 grams/1 mole H) = 26.6 grams hydrogen ================= 17 g of ammonia has 3 g of hydrogen. So 150 g of ammonia will have 26.5 g of hydrogen
Chemical formula of ammonia is NH3; ammonia contain hydrogen and nitrogen.
ammonia = NH3 Therefore, ammonia contains Nitrogen and Hydrogen
When 6,0 moles of H2 gas react with nitrogen, 4 moles of ammonia are produced.
The Synthesis of Ammonia is done through Haber's Process: N2 + 3H2 -> 2NH3 so 2 moles of NH3 requires 3 moles of H2 gas so if X moles of NH3 requires 19.5 moles of H2 gas then X=(2/3)*19.5=13 NH3 formed = 13 moles