8
2xN=2 Nitrogen atoms
+
2xH3=6 Hydrogen atoms
=8 total atoms
1 mole NH3 (3 mole H/1 mole NH3) = 3 mole hydrogen atoms
600 atoms there are 3 atoms of hydrogen per ammonia molecule
In the reaction N2 + 3H2 → 2NH3, nitrogen (N2) is reduced because it gains hydrogen atoms, and hydrogen (H2) is oxidized because it loses electrons.
Four ammonia plus five oxygen molecules yields 4 nitrous oxide plus six water.
There are 20 atoms and there are 6 Carbon atoms, 8 Hydrogen atoms, 6 Oxygen atoms.
There are 2 nitrogen atoms in 2NH3.
1 mole NH3 (3 mole H/1 mole NH3) = 3 mole hydrogen atoms
2NH3 molecules contain a total of 6 hydrogen atoms. This is because each NH3 molecule has 3 hydrogen atoms, and there are 2 NH3 molecules in the given compound.
The product of 2NH3, or two molecules of ammonia, is simply 2NH3 itself. Ammonia (NH3) is a compound consisting of one nitrogen atom and three hydrogen atoms. In chemical reactions, ammonia can participate in various reactions, but in this context, the expression refers to the quantity of ammonia rather than a transformation into different products.
Coefficient-Determines the number of molecules
2NH3 + 2NA = 3H2 + NA3N2
600 atoms there are 3 atoms of hydrogen per ammonia molecule
The balanced equation for this reaction is: N2(g) + 3H2(g) → 2NH3(g).
The balanced symbol equation for the formation of ammonia is: N2 + 3H2 → 2NH3
The bond of reactants that is broken in 2NH3 is the nitrogen-hydrogen (N-H) bond.
N2 + 3H2 -------> 2NH3 Nitrogen is found as N2 in nature. Therefore 6 Hs are needed. Hydrogen is found as H2 and so 3 of these molecules are needed. To balance the 2N atoms and 6H atoms with the product NH3 means 2 ammonia molecules are formed.
The equation for the formation of ammonia is: N2(g) + 3H2(g) -> 2NH3(g)