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Na2CO32 * 2 = 4 moles sodium.===========================
It does NOT form molecules. When AlCl3 'breakdown ' it form the IONS Al^(3+) & 3 Cl^(-) AlCl3(s) IS a molecule.
0.00833 moles of CO3
3(2.6) = 7.8 moles of ions
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Na2CO32 * 2 = 4 moles sodium.===========================
It does NOT form molecules. When AlCl3 'breakdown ' it form the IONS Al^(3+) & 3 Cl^(-) AlCl3(s) IS a molecule.
0.00833 moles of CO3
I suppose that the answers are: - 0,9 moles aluminium ions - 2,7 moles chloride ions
There are 2.8604 moles of ammonium ions in 6.955.
3(2.6) = 7.8 moles of ions
If the solutions have the same molality, the salt will produce twice as many dissolved particles (Na+ ions and Cl- ions) but the sugar does not dissociate into particles when dissolved.
one
2 moles of Ca and 4 moles of OH
Tin(IV)cyanide is Sn(CN)4 and will dissociate into five ions.
There are two moles of sodium ions in two moles of sodium chloride.
The number of moles is 8,00944733981.10e23.