Well first things first you have to balance the equation
Fe3O4-->3Fe+2O2
Then because your given mass is in kg you have to convert it to grams
100.0kgx1,000kg/(over)1g=100,000g or 1.0x105
Next because you have mass of Fe3O4 you need to get the molar mass.
(3)55.85gFe+(4)16.00gO=231.55gFe3O4
Now convert grams to moles for your final answer
1.0x105gFe3O4x1mol/(over)231.55g(mm)x3molFe/(over)1mol Fe=1295.6 mol Fe
you can recover 1295.6moles of Fe from Fe3O4
If you follow the rule of Significant Figures, 100.0kg has 4 significant figures (digits) so your answer needs to have 4 digits
1295.6=1296
you can recover 1296 moles of Fe from Fe3O4
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
is fe3o4 non stoichiometric
Fe3O4 is FeO.Fe2O3 and it is always -2 for Oxygen and +2 for iron (in FeO) and +3 for iron (Fe2O3)
By this following reaction:Fe2+ + Fe3+ + OH- ----> Fe3O4 + H2OIt comes out as a black precipitate. Generally this reaction is done by using Iron(II) Chloride, Iron(III) chloride and Ammonium hydroxide.
FeO, Fe3O4, and Fe2O3
Never. iron shows either +2 or +3 oxidation state but in Fe3O4 its oxidation state is seems to +4 but it is actually mixture of one moles FeO and one mole Fe2O3 , (FeO.Fe2O3 = Fe3O4).
FeO, Fe2O3, Fe3O4 Note: Fe3O4 can be considered as a mixture of FeO and Fe2O3
If 85.65g of iron forms 118.37g of the oxide, the mass of oxygen combined with this mass of iron is 32.72g. Calculate the number of moles of iron and oxygen which have combined (after all, the formula of a compound shows the ratio of the number of moles of each element combined). Do this by dividing the mass reacted by the Relative Atomic Mass of the element concerned. i.e. For Iron it is 85.65/55.8 and for Oxygen 32.72/16. This gives a mole ratio of Fe:O as 1.53:2.04 or 3:4 Therefore the formula is Fe3O4
91.6%
Formula of 3 types of Iron oxides: Iron(II) oxide= FeO Iron(III) oxide= Fe2O3 Iron(II,III) oxide= Fe3O4
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
Fe3O4 (The numbers are subscripts, meaning they are smaller, and go beside the element.)
87.4%
91.6%
Lodestone is Fe3O4-also called magnetite.
is fe3o4 non stoichiometric
These compounds are iron oxides as FeO, Fe2O3, Fe3O4.Rust.