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What is the limiting reagent if 6 moles of magnesium react with 6 moles of nitrogen to form magnesium nitride.?
This is the amount of magnesium.
How many moles of magnesium are in a sample of 56.4 of magnesium?
To determine how many moles of magnesium are in a sample of 56.4 g, you would first calculate the molar mass of magnesium (about 24.3 g/mol). Then, divide the mass of the sample by the molar mass to obtain the number of moles present (around 2.32 moles in this case).
You have a sample of 1.25 g of magnesium hydroxide MgOH 2 How many moles of magnesium hydroxide are there?
0.0214 mol
When magnesium burns in pure nitrogen gas magnesium nitride is formes what mass of magnesium must be provided in order to produce 1.19 grams of magnesium nitride?
To calculate the mass of magnesium needed to produce 1.19 grams of magnesium nitride, you need to consider the stoichiometry of the reaction. The molar mass of Mg3N2 (magnesium nitride) is 100.93 g/mol. From the balanced equation, 6 moles of magnesium is needed to produce 1 mole of magnesium nitride. Therefore, you can use the molar mass of magnesium and molar ratio to determine the mass needed.
How many moles in 13.5 grams of magnesium nitrate?
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
How many moles present in 7.68 grams of calcium nitride?
7,68 grams of calcium nitride is equal to 0,052 moles.
How many moles of lithium nitride are produced when 0.750 mol of lithium react in this fashion?
0,25 moles lithium nitride are obtained.
How many moles are present in 480g of anhydrous magnesium sulfate?
First we calculate the formula mass of the compound magnesium sulfate.Formula mass of MgSO4 = 24.3 + 32.1 + 4(16.0) = 120.4 Amount of MgSO4 in a 480g pure sample = 480/120.4 = 3.99mol There is approximately 4 moles of the compound present in a 480g sample.
How many moles of lithium nitride are produced when 1.450 mo of lithium react?
The balanced chemical equation is 6Li + N2 -> 2Li3N. This means 6 moles of lithium react with 1 mole of nitrogen to produce 2 moles of lithium nitride. Therefore, 1.450 moles of lithium will produce 0.483 moles of lithium nitride.
How many moles of lithium nitride are produced when 0.450 mol of lithium react in the fashion?
This reaction? 6Li + N2 --> 2Li3N 0.450 moles Li (2 moles Li3N/6 moles Li) = 0.150 moles lithium nitride produced ===========================
What is the balanced equation between magnesium nitrogen and magnesium nitride?
3Mn + N2 ----> Mn3N2 its actually 3mg+N2(arrow) Mg3N2
How many grams are in 1.11 moles of magnesium?
1,11 moles of magnesium have 26,97855 g.
