To convert grams to moles you need mercury's atomic mass: 200.59 grams/mole. You can then take your measurement and divide it by the atomic mass to get moles.Grams ÷ Atomic mass = Moles50.15 grams ÷ 200.59 grams = 0.2500 moles Hg
To determine how many moles of mercury are produced when 125 g of oxygen is generated, we first need to know the balanced chemical equation for the reaction involving mercury and oxygen. Assuming the reaction is the formation of mercury(II) oxide (HgO) from mercury (Hg) and oxygen (O₂), the equation is: 2 Hg + O₂ → 2 HgO. Given that the molar mass of oxygen (O₂) is approximately 32 g/mol, 125 g of oxygen corresponds to about 3.91 moles of O₂. According to the stoichiometry of the balanced equation, 2 moles of Hg are produced for every 1 mole of O₂. Therefore, 3.91 moles of O₂ would produce approximately 7.82 moles of Hg.
To determine how many moles of mercury (II) oxide (HgO) are needed to produce 125 g of oxygen (O₂), we first need to consider the decomposition reaction: 2 HgO(s) → 2 Hg(l) + O₂(g). From this equation, we see that 2 moles of HgO produce 1 mole of O₂. The molar mass of O₂ is approximately 32 g/mol, so 125 g of O₂ corresponds to about 3.91 moles (125 g ÷ 32 g/mol). Therefore, since 2 moles of HgO produce 1 mole of O₂, we need 7.82 moles of HgO (3.91 moles O₂ × 2 moles HgO/mole O₂).
978 g calcium contain 24,4 moles.
29,0 g of calcium is equal to 0,723 moles.
To convert grams to moles you need mercury's atomic mass: 200.59 grams/mole. You can then take your measurement and divide it by the atomic mass to get moles.Grams ÷ Atomic mass = Moles50.15 grams ÷ 200.59 grams = 0.2500 moles Hg
You do not say whether it is grammes or kilogrammes. assuming it to be grams. 1.0 x 10^9 g = 1,000,000,000 g The relative atomic mass of mercury is 200.6 Moles = mass (g / Ar Hence moles(Hg) = 1,000,000,000 / 200.6 = 4985044.865 moles.
To determine how many moles of mercury are produced when 125 g of oxygen is generated, we first need to know the balanced chemical equation for the reaction involving mercury and oxygen. Assuming the reaction is the formation of mercury(II) oxide (HgO) from mercury (Hg) and oxygen (O₂), the equation is: 2 Hg + O₂ → 2 HgO. Given that the molar mass of oxygen (O₂) is approximately 32 g/mol, 125 g of oxygen corresponds to about 3.91 moles of O₂. According to the stoichiometry of the balanced equation, 2 moles of Hg are produced for every 1 mole of O₂. Therefore, 3.91 moles of O₂ would produce approximately 7.82 moles of Hg.
To determine how many moles of mercury (II) oxide (HgO) are needed to produce 125 g of oxygen (O₂), we first need to consider the decomposition reaction: 2 HgO(s) → 2 Hg(l) + O₂(g). From this equation, we see that 2 moles of HgO produce 1 mole of O₂. The molar mass of O₂ is approximately 32 g/mol, so 125 g of O₂ corresponds to about 3.91 moles (125 g ÷ 32 g/mol). Therefore, since 2 moles of HgO produce 1 mole of O₂, we need 7.82 moles of HgO (3.91 moles O₂ × 2 moles HgO/mole O₂).
The formula is: number of moles = g Be/9,012.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
573,28 of g of AgCI is equivalent to 4 moles.
67,4 g HCl is equivalent to 1,85 moles.
29,0 g of calcium is equal to 0,723 moles.
27.4 g H2O x 1 mole/18 g = 1.52 moles