You do not say whether it is grammes or kilogrammes. assuming it to be grams.
1.0 x 10^9 g = 1,000,000,000 g
The relative Atomic Mass of Mercury is 200.6
Moles = mass (g / Ar
Hence moles(Hg) = 1,000,000,000 / 200.6 = 4985044.865 moles.
370 grams of mercury is equal to 1,844 moles.
620 grams mercury (1 mole Hg/200.6 grams) = 3.09 moles Hg
To convert grams to moles you need mercury's atomic mass: 200.59 grams/mole. You can then take your measurement and divide it by the atomic mass to get moles.Grams ÷ Atomic mass = Moles50.15 grams ÷ 200.59 grams = 0.2500 moles Hg
603 grams of mercury are equivalent to 3,006 moles.
To determine how many moles of mercury are produced when 125 g of oxygen is generated, we first need to know the balanced chemical equation for the reaction involving mercury and oxygen. Assuming the reaction is the formation of mercury(II) oxide (HgO) from mercury (Hg) and oxygen (O₂), the equation is: 2 Hg + O₂ → 2 HgO. Given that the molar mass of oxygen (O₂) is approximately 32 g/mol, 125 g of oxygen corresponds to about 3.91 moles of O₂. According to the stoichiometry of the balanced equation, 2 moles of Hg are produced for every 1 mole of O₂. Therefore, 3.91 moles of O₂ would produce approximately 7.82 moles of Hg.
To find the moles of mercury (II) oxide (HgO) needed to produce 125 grams of oxygen (O2), we first calculate the moles of O2. The molar mass of O2 is approximately 32 g/mol, so 125 g of O2 corresponds to about 3.91 moles (125 g ÷ 32 g/mol). The decomposition of 2 moles of HgO produces 1 mole of O2, meaning we need 7.82 moles of HgO (3.91 moles O2 × 2) to produce that amount of oxygen. Thus, 7.82 moles of mercury (II) oxide are required.
To determine how many grams of mercury (Hg) are needed to produce 3.75 moles of oxygen (O₂), we first consider the balanced chemical reaction for the formation of oxygen from mercury(II) oxide (HgO): 2 HgO → 2 Hg + O₂. From this, we see that 2 moles of HgO produce 1 mole of O₂, which means 3.75 moles of O₂ require 7.5 moles of Hg. The molar mass of Hg is approximately 200.59 g/mol, so 7.5 moles of Hg would weigh about 1,504.43 grams (7.5 moles × 200.59 g/mol).
To find the number of atoms in 2.36 grams of mercury (Hg), we first need to determine the number of moles of mercury. The molar mass of mercury is approximately 200.59 g/mol. Therefore, 2.36 g of mercury is about 0.0118 moles (2.36 g / 200.59 g/mol). Since one mole contains approximately (6.022 \times 10^{23}) atoms (Avogadro's number), the number of atoms in 2.36 g of mercury is approximately (7.09 \times 10^{21}) atoms.
To determine how many moles of mercury (II) oxide (HgO) are needed to produce 125 g of oxygen (O₂), we first need to consider the decomposition reaction: 2 HgO(s) → 2 Hg(l) + O₂(g). From this equation, we see that 2 moles of HgO produce 1 mole of O₂. The molar mass of O₂ is approximately 32 g/mol, so 125 g of O₂ corresponds to about 3.91 moles (125 g ÷ 32 g/mol). Therefore, since 2 moles of HgO produce 1 mole of O₂, we need 7.82 moles of HgO (3.91 moles O₂ × 2 moles HgO/mole O₂).
Of course 6 moles.
16 grams of oxygen how many moles is 0,5 moles.
moles of what?