0
What else can I help you with?
How many moles of atoms are in 50.15g of mercury atomic mass 200.59 amu?
To convert grams to moles you need mercury's atomic mass: 200.59 grams/mole. You can then take your measurement and divide it by the atomic mass to get moles.Grams ÷ Atomic mass = Moles50.15 grams ÷ 200.59 grams = 0.2500 moles Hg
How many moles of mercury are produced if 125 g of oxygen is also produced?
To determine how many moles of mercury are produced when 125 g of oxygen is generated, we first need to know the balanced chemical equation for the reaction involving mercury and oxygen. Assuming the reaction is the formation of mercury(II) oxide (HgO) from mercury (Hg) and oxygen (O₂), the equation is: 2 Hg + O₂ → 2 HgO. Given that the molar mass of oxygen (O₂) is approximately 32 g/mol, 125 g of oxygen corresponds to about 3.91 moles of O₂. According to the stoichiometry of the balanced equation, 2 moles of Hg are produced for every 1 mole of O₂. Therefore, 3.91 moles of O₂ would produce approximately 7.82 moles of Hg.
How many moles of mercury (II) oxide are needed to produce 125 grams of oxygen?
To find the moles of mercury (II) oxide (HgO) needed to produce 125 grams of oxygen (O2), we first calculate the moles of O2. The molar mass of O2 is approximately 32 g/mol, so 125 g of O2 corresponds to about 3.91 moles (125 g ÷ 32 g/mol). The decomposition of 2 moles of HgO produces 1 mole of O2, meaning we need 7.82 moles of HgO (3.91 moles O2 × 2) to produce that amount of oxygen. Thus, 7.82 moles of mercury (II) oxide are required.
How many atoms are in 2.36g of Mercury?
To find the number of atoms in 2.36 grams of mercury (Hg), we first need to determine the number of moles of mercury. The molar mass of mercury is approximately 200.59 g/mol. Therefore, 2.36 g of mercury is about 0.0118 moles (2.36 g / 200.59 g/mol). Since one mole contains approximately (6.022 \times 10^{23}) atoms (Avogadro's number), the number of atoms in 2.36 g of mercury is approximately (7.09 \times 10^{21}) atoms.
How many moles of mercury (II) oxide are needed to produce 125 g of oxygen?
To determine how many moles of mercury (II) oxide (HgO) are needed to produce 125 g of oxygen (O₂), we first need to consider the decomposition reaction: 2 HgO(s) → 2 Hg(l) + O₂(g). From this equation, we see that 2 moles of HgO produce 1 mole of O₂. The molar mass of O₂ is approximately 32 g/mol, so 125 g of O₂ corresponds to about 3.91 moles (125 g ÷ 32 g/mol). Therefore, since 2 moles of HgO produce 1 mole of O₂, we need 7.82 moles of HgO (3.91 moles O₂ × 2 moles HgO/mole O₂).
How many moles of atoms are in 50.15g of mercury atomic mass 200.59 amu?
To convert grams to moles you need mercury's atomic mass: 200.59 grams/mole. You can then take your measurement and divide it by the atomic mass to get moles.Grams ÷ Atomic mass = Moles50.15 grams ÷ 200.59 grams = 0.2500 moles Hg
How many moles of mercury are in 1.00*10^9?
You do not say whether it is grammes or kilogrammes. assuming it to be grams. 1.0 x 10^9 g = 1,000,000,000 g The relative atomic mass of mercury is 200.6 Moles = mass (g / Ar Hence moles(Hg) = 1,000,000,000 / 200.6 = 4985044.865 moles.
How many moles of mercury are produced if 125 g of oxygen is also produced?
To determine how many moles of mercury are produced when 125 g of oxygen is generated, we first need to know the balanced chemical equation for the reaction involving mercury and oxygen. Assuming the reaction is the formation of mercury(II) oxide (HgO) from mercury (Hg) and oxygen (O₂), the equation is: 2 Hg + O₂ → 2 HgO. Given that the molar mass of oxygen (O₂) is approximately 32 g/mol, 125 g of oxygen corresponds to about 3.91 moles of O₂. According to the stoichiometry of the balanced equation, 2 moles of Hg are produced for every 1 mole of O₂. Therefore, 3.91 moles of O₂ would produce approximately 7.82 moles of Hg.
How many moles of mercury (II) oxide are needed to produce 125 grams of oxygen?
To find the moles of mercury (II) oxide (HgO) needed to produce 125 grams of oxygen (O2), we first calculate the moles of O2. The molar mass of O2 is approximately 32 g/mol, so 125 g of O2 corresponds to about 3.91 moles (125 g ÷ 32 g/mol). The decomposition of 2 moles of HgO produces 1 mole of O2, meaning we need 7.82 moles of HgO (3.91 moles O2 × 2) to produce that amount of oxygen. Thus, 7.82 moles of mercury (II) oxide are required.
How many atoms are in 2.36g of Mercury?
To find the number of atoms in 2.36 grams of mercury (Hg), we first need to determine the number of moles of mercury. The molar mass of mercury is approximately 200.59 g/mol. Therefore, 2.36 g of mercury is about 0.0118 moles (2.36 g / 200.59 g/mol). Since one mole contains approximately (6.022 \times 10^{23}) atoms (Avogadro's number), the number of atoms in 2.36 g of mercury is approximately (7.09 \times 10^{21}) atoms.
How many moles of mercury (II) oxide are needed to produce 125 g of oxygen?
To determine how many moles of mercury (II) oxide (HgO) are needed to produce 125 g of oxygen (O₂), we first need to consider the decomposition reaction: 2 HgO(s) → 2 Hg(l) + O₂(g). From this equation, we see that 2 moles of HgO produce 1 mole of O₂. The molar mass of O₂ is approximately 32 g/mol, so 125 g of O₂ corresponds to about 3.91 moles (125 g ÷ 32 g/mol). Therefore, since 2 moles of HgO produce 1 mole of O₂, we need 7.82 moles of HgO (3.91 moles O₂ × 2 moles HgO/mole O₂).
If you have g of beryllium how many moles is this equivalent to?
The formula is: number of moles = g Be/9,012.
How many moles are in 27.4 g of water?
27.4 g H2O x 1 mole/18 g = 1.52 moles
How many moles are in 978 g Ca?
978 g calcium contain 24,4 moles.
How many moles are in 29.0 g of calcium?
29,0 g of calcium is equal to 0,723 moles.
How many moles are in 67.4 g of HCI?
67,4 g HCl is equivalent to 1,85 moles.
How many moles are in 14.84 g Mg?
14,84 g magnesium are equivalent to 0,61 moles.
