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8.02 / 16.04 = 0.5 moles
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How many moles are in 0.289 g of methane?
To find the number of moles in 0.289 g of methane, first calculate the molar mass of methane (CH4), which is approximately 16 g/mol. Next, divide the given mass (0.289 g) by the molar mass to obtain the number of moles. Therefore, 0.289 g of methane is equivalent to 0.289 g / 16 g/mol ≈ 0.018 moles of methane.
Which of the following shows that the combustion of methane produces 802 kJ mol of energy?
CH4(g) + 2O2(g) CO2(g) + 2H2O(g) + 802 kJ/mol
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
The balanced chemical equation for the combustion of methane is: CH4 + 2O2 -> CO2 + 2H2O From the equation, 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane is 16 g/mol, so 100.0 grams of methane is 100.0/16 = 6.25 moles. Therefore, 6.25 moles of carbon dioxide will be produced.
If in the previous problem only 25.9 grams of water vapor were formed how much methane actually reacted with oxygen?
Methane and oxygen react according to the equation:CH4 + 2O2 -->CO2 + 2H2O Thus 1 mole of methane produces 2 moles of water. 25.9 g of water is 25.9/18 moles = 1.44 moles.So we must have started with 0.72 moles of methane, which is 0.72 x 16 g= 11.51 g of methane.
The formula for methane is CH4. Four moles of methane would have a mass of how many grams?
Taking carbon @ 12.01 g/mol & hydrogen @ 1.01 g/ mol methane has 1 carbon & 4 hydrogen, so it is:12.01g + 4(1.01g) = 16.05g per mole.For 4 moles: 4 x 16.05 g = 64.20 g
How many moles are in 0.289 g of methane?
To find the number of moles in 0.289 g of methane, first calculate the molar mass of methane (CH4), which is approximately 16 g/mol. Next, divide the given mass (0.289 g) by the molar mass to obtain the number of moles. Therefore, 0.289 g of methane is equivalent to 0.289 g / 16 g/mol ≈ 0.018 moles of methane.
Which of the following shows that the combustion of methane produces 802 kJ mol of energy?
CH4(g) + 2O2(g) CO2(g) + 2H2O(g) + 802 kJ/mol
If in the previous problem only 25.9 grams of water vapor were formed how much methane actually reacted with oxygen?
Methane and oxygen react according to the equation:CH4 + 2O2 -->CO2 + 2H2O Thus 1 mole of methane produces 2 moles of water. 25.9 g of water is 25.9/18 moles = 1.44 moles.So we must have started with 0.72 moles of methane, which is 0.72 x 16 g= 11.51 g of methane.
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
The balanced chemical equation for the combustion of methane is: CH4 + 2O2 -> CO2 + 2H2O From the equation, 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane is 16 g/mol, so 100.0 grams of methane is 100.0/16 = 6.25 moles. Therefore, 6.25 moles of carbon dioxide will be produced.
The formula for methane is CH4. Four moles of methane would have a mass of how many grams?
Taking carbon @ 12.01 g/mol & hydrogen @ 1.01 g/ mol methane has 1 carbon & 4 hydrogen, so it is:12.01g + 4(1.01g) = 16.05g per mole.For 4 moles: 4 x 16.05 g = 64.20 g
How many liters of oxygen are needed to exactly react with 27.8 g of methane at STP?
To convert 27.8 g of methane to moles, use the molar mass of methane (CH4) to find that 27.8 g is about 0.69 moles. The balanced chemical equation for the reaction between methane and oxygen is: CH4 + 2O2 -> CO2 + 2H2O. This means that each mole of methane reacts with 2 moles of oxygen. So, 0.69 moles of methane would react with 1.38 moles of oxygen. At STP, 1 mole of gas occupies 22.4 liters, so 1.38 moles of oxygen would occupy 30.912 liters.
How many moles does 3.80 g Zn have?
3,80 g Zn have 0,058 moles.
If you have g of beryllium how many moles is this equivalent to?
The formula is: number of moles = g Be/9,012.
How many moles of argon are in 24.7 g of argon?
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
What are the steps needed to convert 77.2 grams of methane to molecules of methane. Please wrote them out ( indluding tchart)?
Step1: Find molar mass of methane, CH4. C=12; H=1; 12+1+1+1+1 = 16 g/moleStep2: Convert grams to moles. 77.2 g x 1 mole/16 g = 4.825 moles methaneStep3: Convert moles to molecules using Avogadro's number.4.825 moles x 6.02x10^23 molecules/mole = 2.90x10^24 moleculesUnfortunately, I don't know what a tchart is, so I didn't include it.
How many moles are in 23.34 g of NaCl?
The answer is 0,4 moles.
How many moles of CCl4 are there in 56 g?
The answer is 0,364 moles.
