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How many moles of CCL4 are there in 56 grams?
Divide the Molar Mass of C and Cl4 by 56 to get your awnswer!
How many moles of CCl4 are present in 22.5 g of the compound?
For this conversion, you need the atomic masses of the elements involved, found on any periodic table. Then you add them up with their abundance in the compound to find the total molar (molecular) mass. The molar mass is the mass in grams of one mole of the compound. Carbon = 12.0 grams Chlorine = 35.5 grams × 4 atoms = 142.0 grams ------------------------------------------------------------- Carbon tetrachloride = 154.0 grams/mole Then you do a gram --> mole conversion, taking the amount given and dividing it by the molar mass. Grams ÷ Molar mass = Moles 22.5 grams ÷ 154.0 grams = 0.146 moles CCl4
What mass of CCl4 is formed by the reaction of 5.14 g of methaneCH4?
The balanced equation for the reaction is: CH4 + 4Cl2 -> CCl4 + 4HCl. 1 mole of CH4 produces 1 mole of CCl4. Calculate moles of CH4: 5.14 g / 16.04 g/mol = 0.32 mol. 0.32 mol of CH4 will produce 0.32 mol of CCl4, which is 0.32 * 153.82 g/mol = 49.18 g of CCl4.
How many molecules of carbon tetrachloride are in 6.32 mg of that compound?
1. Convert 6.32 mg to grams.6.32 mg x 1g/1000 mg = 0.00632 g2. Determine the molar mass for CCl4.The molar mass is 153.82g/mol (Wikipedia)3. Convert given mass to moles using the molar mass.0.00632 g CCl4 x 1 mol CCl4/153.82 g CCl4 = 4.11 x 10^-5 mol CCl44. Convert moles to molecules.One mole of molecules is 6.022 x 10^23 molecules.4.11 x 10^-5 mol CCl4 x 6.022 x 10^23 molecules CCl4/mol CCl4 = 2.47 x 10^19 molecules CCl4
How many moles of aluminum are present in an aluminum cylinder with a mass of 15 g?
To determine the number of moles of aluminum present, we need to first determine the molar mass of aluminum, which is approximately 26.98 g/mol. We can then use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 15 g / 26.98 g/mol ≈ 0.56 moles of aluminum.
How many moles of CCL4 are there in 56 grams?
Divide the Molar Mass of C and Cl4 by 56 to get your awnswer!
How many moles of CCl4 are present in 22.5 g of the compound?
For this conversion, you need the atomic masses of the elements involved, found on any periodic table. Then you add them up with their abundance in the compound to find the total molar (molecular) mass. The molar mass is the mass in grams of one mole of the compound. Carbon = 12.0 grams Chlorine = 35.5 grams × 4 atoms = 142.0 grams ------------------------------------------------------------- Carbon tetrachloride = 154.0 grams/mole Then you do a gram --> mole conversion, taking the amount given and dividing it by the molar mass. Grams ÷ Molar mass = Moles 22.5 grams ÷ 154.0 grams = 0.146 moles CCl4
How many mass of carbon tetrachloride?
2,74 moles of CCL4 is equivalent to 421,44 g.
What mass of CCl4 is formed by the reaction of 5.14 g of methaneCH4?
The balanced equation for the reaction is: CH4 + 4Cl2 -> CCl4 + 4HCl. 1 mole of CH4 produces 1 mole of CCl4. Calculate moles of CH4: 5.14 g / 16.04 g/mol = 0.32 mol. 0.32 mol of CH4 will produce 0.32 mol of CCl4, which is 0.32 * 153.82 g/mol = 49.18 g of CCl4.
How many grams of ccl4 are needed to have 5.000 mol?
To find the grams of CCl4 needed, multiply the number of moles (5.000 mol) by the molar mass of CCl4 (153.82 g/mol). (5.000 , \text{mol} \times 153.82 , \text{g/mol} = 769.1 , \text{g}) Therefore, 769.1 grams of CCl4 are needed.
How many moles are there in 8.52 grams of carbon tetrachloride?
To determine the number of moles in 8.52 grams of carbon tetrachloride, divide the given mass by the molar mass of carbon tetrachloride. The molar mass of carbon tetrachloride (CCl4) is 153.82 g/mol. Therefore, 8.52 grams of CCl4 is equal to 0.055 moles.
What is the molar mass of adrenaline in a solution of 0.64 g of adrenaline in 36.0 g of CCl4 elevates the boiling point by 0.49?
First, calculate the molality of the adrenaline solution in CCl4 using the elevation in boiling point. Then, determine the moles of adrenaline in the solution using the molality and mass of CCl4. Finally, divide the mass of adrenaline by the moles to find the molar mass.
How many molecules of carbon tetrachloride are in 6.32 mg of that compound?
1. Convert 6.32 mg to grams.6.32 mg x 1g/1000 mg = 0.00632 g2. Determine the molar mass for CCl4.The molar mass is 153.82g/mol (Wikipedia)3. Convert given mass to moles using the molar mass.0.00632 g CCl4 x 1 mol CCl4/153.82 g CCl4 = 4.11 x 10^-5 mol CCl44. Convert moles to molecules.One mole of molecules is 6.022 x 10^23 molecules.4.11 x 10^-5 mol CCl4 x 6.022 x 10^23 molecules CCl4/mol CCl4 = 2.47 x 10^19 molecules CCl4
How many moles of aluminum are present in an aluminum cylinder with a mass of 15 g?
To determine the number of moles of aluminum present, we need to first determine the molar mass of aluminum, which is approximately 26.98 g/mol. We can then use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 15 g / 26.98 g/mol ≈ 0.56 moles of aluminum.
How many grams of koh are needed to prepare 250 milliliters of a 2 m solution of koh formula mass 56?
To prepare a 2 M solution of KOH, you would need to calculate the moles of KOH required first. Then use the formula mass of KOH (56 g/mol) to convert moles to grams. First, calculate the moles needed: 2 moles/L * 0.25 L = 0.5 moles. Then, convert moles to grams: 0.5 moles * 56 g/mole = 28 grams of KOH needed.
How many atoms are present in 21.7g of carbon tetrachloride?
21.7 g CCl4 (1 mole CCl4/153.81 g)(6.022 X 1023/1 mole CCl4) = 8.50 X 1022 atoms of carbon tetrachloride ===========================
What is the number of moles of gas in 56.0 L of oxygen at STP?
4 g of Helium = 1 mole.So, 56 g of helium = 14 moles
