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The answer is 0,364 moles.
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∙ 9y ago
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How many moles of aluminum are present in an aluminum cylinder with a mass of 15 g?
The Answer is.56 moles OR 0.56 moles
How many molecules of carbon tetrachloride are in 6.32 mg of that compound?
1. Convert 6.32 mg to grams.6.32 mg x 1g/1000 mg = 0.00632 g2. Determine the molar mass for CCl4.The molar mass is 153.82g/mol (Wikipedia)3. Convert given mass to moles using the molar mass.0.00632 g CCl4 x 1 mol CCl4/153.82 g CCl4 = 4.11 x 10^-5 mol CCl44. Convert moles to molecules.One mole of molecules is 6.022 x 10^23 molecules.4.11 x 10^-5 mol CCl4 x 6.022 x 10^23 molecules CCl4/mol CCl4 = 2.47 x 10^19 molecules CCl4
What mass of CCl4 is formed by the reaction of 5.14 g of methaneCH4?
The answer is 49,29 g CCl4.
How many moles of CCl4 are present in 22.5 g of the compound?
For this conversion, you need the atomic masses of the elements involved, found on any periodic table. Then you add them up with their abundance in the compound to find the total molar (molecular) mass. The molar mass is the mass in grams of one mole of the compound. Carbon = 12.0 grams Chlorine = 35.5 grams × 4 atoms = 142.0 grams ------------------------------------------------------------- Carbon tetrachloride = 154.0 grams/mole Then you do a gram --> mole conversion, taking the amount given and dividing it by the molar mass. Grams ÷ Molar mass = Moles 22.5 grams ÷ 154.0 grams = 0.146 moles CCl4
How many moles does 3.80 g Zn have?
3,80 g Zn have 0,058 moles.
How many mass of carbon tetrachloride?
2,74 moles of CCL4 is equivalent to 421,44 g.
How many moles of aluminum are present in an aluminum cylinder with a mass of 15 g?
The Answer is.56 moles OR 0.56 moles
How many molecules of carbon tetrachloride are in 6.32 mg of that compound?
1. Convert 6.32 mg to grams.6.32 mg x 1g/1000 mg = 0.00632 g2. Determine the molar mass for CCl4.The molar mass is 153.82g/mol (Wikipedia)3. Convert given mass to moles using the molar mass.0.00632 g CCl4 x 1 mol CCl4/153.82 g CCl4 = 4.11 x 10^-5 mol CCl44. Convert moles to molecules.One mole of molecules is 6.022 x 10^23 molecules.4.11 x 10^-5 mol CCl4 x 6.022 x 10^23 molecules CCl4/mol CCl4 = 2.47 x 10^19 molecules CCl4
What mass of CCl4 is formed by the reaction of 5.14 g of methaneCH4?
The answer is 49,29 g CCl4.
How many atoms are present in 21.7g of carbon tetrachloride?
21.7 g CCl4 (1 mole CCl4/153.81 g)(6.022 X 1023/1 mole CCl4) = 8.50 X 1022 atoms of carbon tetrachloride ===========================
What is the number of moles of gas in 56.0 L of oxygen at STP?
4 g of Helium = 1 mole.So, 56 g of helium = 14 moles
How many moles of CCl4 are present in 22.5 g of the compound?
For this conversion, you need the atomic masses of the elements involved, found on any periodic table. Then you add them up with their abundance in the compound to find the total molar (molecular) mass. The molar mass is the mass in grams of one mole of the compound. Carbon = 12.0 grams Chlorine = 35.5 grams × 4 atoms = 142.0 grams ------------------------------------------------------------- Carbon tetrachloride = 154.0 grams/mole Then you do a gram --> mole conversion, taking the amount given and dividing it by the molar mass. Grams ÷ Molar mass = Moles 22.5 grams ÷ 154.0 grams = 0.146 moles CCl4
How many molecules are in 22.4 grams of CCL4?
The molar mass of CCl4 is 153,82 g.153,82 ------------------------------------6,02214129.10ex.23 (Avogadro number)22,4 g-------------------------------------xx = 0,877.10ex.23 molecules
How many moles does 3.80 g Zn have?
3,80 g Zn have 0,058 moles.
If you have g of beryllium how many moles is this equivalent to?
The formula is: number of moles = g Be/9,012.
How many moles of argon are in 24.7 g of argon?
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
How many moles are in 19.2 g of CS2?
The answer is 0,253 moles.
