0
For this conversion, you need the atomic masses of the elements involved, found on any Periodic Table. Then you add them up with their abundance in the compound to find the total molar (molecular) mass. The molar mass is the mass in grams of one mole of the compound. Carbon = 12.0 grams Chlorine = 35.5 grams × 4 atoms = 142.0 grams ------------------------------------------------------------- Carbon tetrachloride = 154.0 grams/mole Then you do a gram --> mole conversion, taking the amount given and dividing it by the molar mass. Grams ÷ Molar mass = Moles 22.5 grams ÷ 154.0 grams = 0.146 moles CCl4
What else can I help you with?
How many moles of CCl4 are there in 56 g?
To find the number of moles, you need to divide the given mass (in grams) by the molar mass of CCl4, which is 153.82 g/mol. Therefore, 56 g / 153.82 g/mol = 0.364 moles of CCl4.
How many moles of CCL4 are there in 56 grams?
Divide the Molar Mass of C and Cl4 by 56 to get your awnswer!
How many molecules of carbon tetrachloride are in 6.32 mg of that compound?
1. Convert 6.32 mg to grams.6.32 mg x 1g/1000 mg = 0.00632 g2. Determine the molar mass for CCl4.The molar mass is 153.82g/mol (Wikipedia)3. Convert given mass to moles using the molar mass.0.00632 g CCl4 x 1 mol CCl4/153.82 g CCl4 = 4.11 x 10^-5 mol CCl44. Convert moles to molecules.One mole of molecules is 6.022 x 10^23 molecules.4.11 x 10^-5 mol CCl4 x 6.022 x 10^23 molecules CCl4/mol CCl4 = 2.47 x 10^19 molecules CCl4
How many moles of H2O are present in 75.0g H2O?
There are 4.17 moles of H2O present in 75.0g of H2O.
How many molecules of dinitrogen monoxide are present in 2.30 moles of this compound?
There are (1.39 \times 10^{24}) molecules of dinitrogen monoxide in 2.30 moles of the compound, calculated by multiplying Avogadro's number (6.022 x 10^23 molecules/mole) by the number of moles provided.
How many atoms of chlorine are in 2.00 moles of CCl4?
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
How many moles of CCl4 are there in 56 g?
To find the number of moles, you need to divide the given mass (in grams) by the molar mass of CCl4, which is 153.82 g/mol. Therefore, 56 g / 153.82 g/mol = 0.364 moles of CCl4.
How many moles of CCL4 are there in 56 grams?
Divide the Molar Mass of C and Cl4 by 56 to get your awnswer!
How many MOLES of sodium nitrate are present in 2.85 grams of this compound?
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
How many grams of phosphorus trichloride are present in 3.42 moles of this compound?
3,42 moles of phosphorus trichloride have 469,6686 g.
How many MOLES of dinitrogen tetraoxide are present in 4.00 grams of this compound?
Dinitrogen tetraoxide, or N2O4 has a molar mass of 92.011 grams per mole. This means there are 0.0435 moles present.
How many molecules of carbon tetrachloride are in 6.32 mg of that compound?
1. Convert 6.32 mg to grams.6.32 mg x 1g/1000 mg = 0.00632 g2. Determine the molar mass for CCl4.The molar mass is 153.82g/mol (Wikipedia)3. Convert given mass to moles using the molar mass.0.00632 g CCl4 x 1 mol CCl4/153.82 g CCl4 = 4.11 x 10^-5 mol CCl44. Convert moles to molecules.One mole of molecules is 6.022 x 10^23 molecules.4.11 x 10^-5 mol CCl4 x 6.022 x 10^23 molecules CCl4/mol CCl4 = 2.47 x 10^19 molecules CCl4
If 3.50 of the unknown compound contained 0.117 of C and 0.233 of H how many moles of oxygen were in the sample?
To find the moles of oxygen in the compound, first calculate the moles of carbon and hydrogen using their respective molar masses. Then, subtract these totals from the total moles present in the compound to find the moles of oxygen.
How many moles are there in 8.52 grams of carbon tetrachloride?
To determine the number of moles in 8.52 grams of carbon tetrachloride, divide the given mass by the molar mass of carbon tetrachloride. The molar mass of carbon tetrachloride (CCl4) is 153.82 g/mol. Therefore, 8.52 grams of CCl4 is equal to 0.055 moles.
How many moles of MgCl2 are there in 313 g of the compound?
Approx 3.29 moles.
How many moles of Al2O3 are present in 49.3 g of this compound?
To find the number of moles, we need to use the molar mass of Al2O3, which is 101.96 g/mol. Divide the given mass (49.3 g) by the molar mass to get the number of moles of Al2O3 present. 49.3 g / 101.96 g/mol ≈ 0.483 moles of Al2O3.
How many moles of H2O are present in 150.0G of H2O?
The answer is 8,33 moles.
