Molar mass of Fe(NO3)2 is 55.85 + 2(14.00 + 3(16.00)) = 179.85 g/mol Therefore, number of moles of Fe(NO3)2 present is 53.55/179.85 = 0.2977 mol For each molecule of Fe(NO3)2, there are two atoms of nitrogen associated with it. Therefore, there are 0.2977*2 = 0.5954 mol of nitrogen atoms
6.226 x 10^28 atoms of Nitrogen approximately mole = 6.226 X 10^28 objects Nitrogen exists as a diatomic molecule, so in 0.5 moles of diatomic nitrogen gas there are exactly 1 moles worth of molecules, therefore the number of atoms in 0.5 moles of nitrogen gas is equal to the value of the mole which is approximately 6.226 x 10 ^ 28 atoms
The number of atoms is 15,11.10EX23.
Are you familiar with mole concept. Well according to it 1 mole of anysubstance contains 6.023e23. First calculate the molecular mass of glucose which is (6*12)+12+(6*16)=180=y gm(say). Now find the mass of the sample glucose say x gm. Calculate the number of moles of glucose present which is found out by x/y. If its exactly 1 mole then the number of carbon atoms present are 6.023e23. Else use unitary method to find out for other values. For your mentioned number of carbon atoms the 0.0021 moles of glucose present.
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
We know from looking at the molecular formula that one mole of molecules of H2SO4 contains 2 moles of atoms of hydrogen, 1 mole of atoms of sulfur and 4 moles of atoms of oxygen.
1.38 moles of nitrogen equal16,62110876532.1023 atoms; the molecule of nitrogen is diatomic.
3 x 12 = 36 moles of Nitrogen atoms N or 18 moles of Nitrogen molecules N2
1.38 moles of nitrogen equal16,62110876532.1023 atoms; the molecule of nitrogen is diatomic.
44 moles of atoms
1 mole=6.02*1023 molecules or atoms5.23 moles=6.02*1023 * 5.23= {[(3.14846*1024molecules)]}
There is one atom in nitrogen there is not one atom of nitrogen, there is one molecule of nitrogen. There is 6.02 * 10^23 atoms in 1 mole of nitrogen. Or simply the natural state of nitrogen is n2. or two nitrogen atoms to a molecule. =]
first find the number of moles of nitrogen in 1.00g than times by 6.02*10^23 n(N)=1/14 * 6.02*10^23 =4.2*10^22 atoms
how many moles of sulfur are present in 3.4 moles of Al2(SO4)3
1.8x10^24 atoms of N
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
Your compound's chemical formula is (NH4)2Cr2O7 - so you can see that it contains 2 moles of NH4+ per mole of the salt. So in 7 moles you have 14 moles of ammonium, containing 14 moles of N atoms which means that you have (1 mole = 6,022*10^23 atoms) 14 mols * 6,022*10^23 atoms/mole = 8,43*10^23 atoms
The answer is 24,92 g nitrogen.