Your compound's chemical formula is (NH4)2Cr2O7 - so you can see that it contains 2 moles of NH4+ per mole of the salt. So in 7 moles you have 14 moles of ammonium, containing 14 moles of N atoms which means that you have
(1 mole = 6,022*10^23 atoms)
14 mols * 6,022*10^23 atoms/mole = 8,43*10^23 atoms
There is one atom in nitrogen there is not one atom of nitrogen, there is one molecule of nitrogen. There is 6.02 * 10^23 atoms in 1 mole of nitrogen. Or simply the natural state of nitrogen is n2. or two nitrogen atoms to a molecule. =]
The answer is 24,92 g nitrogen.
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
1.5 moles of N2O5 Each molecule of NO3 contains one atom of nitrogen, so 3 moles of the compound will contain 3 moles of N atoms. However, N2O5 molecules each contain two nitrogen atoms, so each mole of N2O5 has two moles of nitrogen. So, in order to have three moles of N atoms, you need only 3/2 = 1.5 moles of N2O5.
There are two nitrogen atoms in one formula unit of Na2Cl. The molar mass of nitrogen is approximately 14.01 g/mol. Therefore, the total mass of nitrogen in 76.0 moles of Na2Cl is 76.0 moles x (2 nitrogen atoms / 1 formula unit) x (14.01 g/mol) = 2121.52 g.
1.38 moles of nitrogen equal16,62110876532.1023 atoms; the molecule of nitrogen is diatomic.
3 x 12 = 36 moles of Nitrogen atoms N or 18 moles of Nitrogen molecules N2
1.38 moles of nitrogen equal16,62110876532.1023 atoms; the molecule of nitrogen is diatomic.
44 moles of atoms
1 mole=6.02*1023 molecules or atoms5.23 moles=6.02*1023 * 5.23= {[(3.14846*1024molecules)]}
Molar mass of Fe(NO3)2 is 55.85 + 2(14.00 + 3(16.00)) = 179.85 g/mol Therefore, number of moles of Fe(NO3)2 present is 53.55/179.85 = 0.2977 mol For each molecule of Fe(NO3)2, there are two atoms of nitrogen associated with it. Therefore, there are 0.2977*2 = 0.5954 mol of nitrogen atoms
There is one atom in nitrogen there is not one atom of nitrogen, there is one molecule of nitrogen. There is 6.02 * 10^23 atoms in 1 mole of nitrogen. Or simply the natural state of nitrogen is n2. or two nitrogen atoms to a molecule. =]
first find the number of moles of nitrogen in 1.00g than times by 6.02*10^23 n(N)=1/14 * 6.02*10^23 =4.2*10^22 atoms
how many moles of sulfur are present in 3.4 moles of Al2(SO4)3
1.8x10^24 atoms of N
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
The answer is 24,92 g nitrogen.