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Balanced equation: 2H2S + 302 = 2SO2 + 2H20
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
Here is the BALANCED reaction eq'n. 2H2(g) + O2(g) = 2H2O(l) The prefix number are the Molar Ratios 2:1::2 So oxygen is ONE(1) mole Hence hydrogen is TWO(2) moles It produces TWO(2) moles of water.
Assuming that all gases in this reaction are at STP, what number of molecules of hydrogen chloride gas are needed to completely react with oxygen to yield 50.00 mL of chlorine
4 C3H8 + 20 O2 ---> 12 CO2 + 16 H2O So 20 mol of O2 are needed.
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
1 mole
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
The nunber of moles of oxygen is 2,5.
N2 + 3H2 -> 2NH3 3 moles hydrogen gas. You should know that because of the formula of ammonia.
8,75 moles of oxygen are needed.
Glucose is C6H12O6 and thus the mole ratio is 6 moles of carbon to 6 moles of Hydrogen Molecules (12 moles of Hydrogen atoms) and 3 moles of oxygen molecules (6 moles of oxygen atoms)
I was wondering about this... but I think if you combined..The four oxygen gas O2, and the two of Hydrogen gas H2.. and predict was will happened I guess this is what it will or might be calculate, but Im not sure.KKKO2O2+H2H1O4+H2O2H
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
Here is the BALANCED reaction eq'n. 2H2(g) + O2(g) = 2H2O(l) The prefix number are the Molar Ratios 2:1::2 So oxygen is ONE(1) mole Hence hydrogen is TWO(2) moles It produces TWO(2) moles of water.
Absolutely none, as there is no oxygen in hydrogen cyanide. Its formula is HCN--one atom each of hydrogen, carbon and nitrogen.
Assuming that all gases in this reaction are at STP, what number of molecules of hydrogen chloride gas are needed to completely react with oxygen to yield 50.00 mL of chlorine