Top Answer
User Avatar
Wiki User
Answered 2012-01-30 19:57:37

2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.

User Avatar

Your Answer

Still Have Questions?

Related Questions

How many moles of oxygen are produced when 7.5 moles of potassium chlorate decompose completely?

Potassium chlorate = KClO3Decompostion: 2KClO3 ==> 3O2 + 2KCl7.5 moles KClO3 x 3 mole O2/2 moles KClO3 = 11.25 moles O2

How many grams of potassium chlorate would be produced by reacting 500 grams of potassium chlorate with oxygen gas?

Nothing is produced, 500g potassium chlorate will be the same 500 g potassium chlorate after reaction. Actually there is no reaction at all.

How many moles of O2 are produced by the decomposition if 10 moles potassium chlorate 2KClO3- and 2KCl plus 3O2?

15 moles of O2 are produced by the decomposition if 10 moles potassium chlorate 2 KClO3 and 2 KCl plus 3O2.

How many moles of oxygen gas will be produced from 25.6 moles of potassium chlorate?

The reaction is:2 KClO3 = 2 KCl + 3 O238,4 moles of oxygen are produced.

How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?

2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3

What gas is produced when you mix hydrogen peroxide with potassium iodide?

Oxygen gas is produced. The hydrogen peroxide will decompose to give water and oxygen, potassium Iodide is acting as a catalyst 2H2O2(l) ------> 2H2O(l) + O2(g)

How many moles of oxygen would be produced by 1.2 moles of KClO3?

A balanced equation for the reaction is 2 KClO3 -> 2 KCl + 3 O2. Therefore, each mole of potassium chlorate produces 3/2 moles of oxygen, and 1.2 moles of potassium chlorate produces (3/2)1.2 or 1.8 moles of oxygen.

How many moles of oxygen are produced from twelve moles of potassium chlorate?

12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.

How many moles of oxygen gas are created if 12.3 moles of potassium chlorate decompose?

The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate

How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?

You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed

What happens if you put potassium in acid?

It is a vigorous and exothermic reaction, in which a salt of Potassium and Hydrogen is produced. The heat produced may be enough to burn the hydrogen produced.

How is oxygen gas prepared in laboratory?

Oxygen can be prepared in the laboratory by red mercuric oxide, or by heating Potassium Chlorate in a test tube in the presence of Maganesedioxide. Fit a test tube with a delivery tube and place the delivery tube under a gas jar filled with water and placed on beehive shelve in a water tub. Heat the test tube containing Potassium Chlorate and Maganesedioxide. The oxygen produced in this reaction is passing through the delivery tube to the gas jar by the downward displacement of water.

When 36.3 g of potassium chlorate is heated 22.1 g of potassium chloride is produced What mass of oxygen is produced?

Equation: 2KClO3 + Cl2 ---> 2KCl + 3O2 + Cl2 1. Solve for the number of moles of KClO3 in 36.3 g. (.2962 molKClO3) 2. Multiply that value by (3/2), from the equation's coefficients. (.4447 molO2) Note: A BCA table could also be used. 3. Solve for the mass of .4447 molO2. 14.2 grams of oxygen would be produced.

A How many moles of O2 were produced b What percent of the mixture was KClO3 and KCl?

A 1.80-gram mixture of potassium chlorate, kclo3, and potassium chloride, kcl, was heated until all of the kclo3 had decomposed the liberated oxygen, after drying, occupied 405 ml at 25C when the barometric pressure was 745 torr. This is the problem and the questions were... a. How many moles of O2 were produced? b. What percent of the mixture was KClO3? KCl? Please help!!

How does phosphorus and potassium produced?

they are found in ores which are put in furnaces to extract the potassium and phosphorus.

How many moles of oxygen are produced from 14 moles of potassium chlorate?

2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.

Still have questions?

Trending Questions
Who was Anna Kreisling? Asked By Wiki User
Unanswered Questions
What plug replaces l8rtc? Asked By Wiki User
Who are perceptual region's? Asked By Wiki User