4NH3 + 3O2 -----> 2N2 + 6H2O
4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
16.0 g
How many grams of oxygen are needed to react completely with 200.0 g of ammonia, NH3?4NH3(g) + 5O2(g) => 4NO(g) + 6H2O(g)
1 mole of gas occupies 22.4 liters at STP. Therefore 3.5/22.4 = 0.15625 moles of SO2. There are thus 0.15625 moles of O2 needed to react with solid sulfur because S + O2 ---->SO2. 0.15625 moles of oxygen occupies 0.15625 x 22.4 liters = 3.5 liters O2 required.
1.5 moles of O2 react with 2 moles of Al 2Al + 1.5 O2 = Al2O3.
.913 moles
16.0 g
How many grams of oxygen are needed to react completely with 200.0 g of ammonia, NH3?4NH3(g) + 5O2(g) => 4NO(g) + 6H2O(g)
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
The nunber of moles of oxygen is 2,5.
The answer is 3,375 moles oxygen.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
The answer is 0,8 moles oxygen.
N2 + 3H2 -> 2NH3 3 moles hydrogen gas. You should know that because of the formula of ammonia.
How many moles of C are needed to react with 0.490 mole SO2?
65
Balanced equation first. 2CH4O + 3O2 -> 2CO2 + 4H2O 23.5 moles methanol (3 moles O2/2 mole CH4O) = 35.3 moles oxygen needed --------------------------------------